In a hydrogen fuel cell, the steps of the chemical reaction are
at-electrode:H2+2OH-2H2O+2e-at+electrode:12O2+H2O+2e-2OH-

Calculate the voltage of the cell. What is the minimum voltage required for electrolysis of water? Explain briefly.

Short Answer

Expert verified

The minimum voltage required is We=1.23 eV

Step by step solution

01

Given Information

Given reaction is

at-electrode:H2+2OH-2H2O+2e-at+electrode:12O2+H2O+2e-2OH-

And Gibbs energy is +237 kJ.

02

Explanation

Gibbs free energy can be written as work done as

ΔG = W ....................................(1)

The expression for the work done by each electron is written as

We = W /(2NA) ...............................(2)

Where We is the work done per electron and NA is Avogadro's number.

As ΔG= 237kJ so W= 237kJ.

Substitute W=237 kJ and NA=6.023 x 1023

We=237kJ26.623×1023=237kJ1000J1kJ26.623×1023=1.968×10-19J1019eV1.6(1J)=1.23eV

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