Calculate the Helmholtz free energy of a van der Waals fluid, up to an undetermined function of temperature as in equation5.56. Using reduced variables, carefully plot the Helmholtz free energy (in units of NkTc) as a function of volume for T/Tc=0.8Identify the two points on the graph corresponding to the liquid and gas at the vapor pressure. (If you haven't worked the preceding problem, just read the appropriate values off Figure5.23.) Then prove that the Helmholtz free energy of a combination of these two states (part liquid, part gas) can be represented by a straight line connecting these two points on the graph. Explain why the combination is more stable, at a given volume, than the homogeneous state represented by the original curve, and describe how you could have determined the two transition volumes directly from the graph of F.

Short Answer

Expert verified

The Helmholtz free energy is:

F=xFl+(1-x)Fg=Fg-xFg-Fl

Step by step solution

01

Given information

We have been givenF=G-PVfor any type of system, we can use gibbs free energy.

02

Simplify

Terms used in this:

Pin terms of V:

F=-NkTln(V-Nb)+(NkT)(Nb)V-Nb-2aN2V-PV+c(T)

when we put the expression in terms of dimensionless variable

=-tln(3v-1)-98v+f(t)

To plot this function we use

Plot[-.8*log[3v-1]-9/(8v),{v,.4,6}]

Then the total volume of the system is:

F=xFl+(1-x)Fg=Fg-xFg-Fl

On elimination x from equation ,we get:

F=Fg-Vg-VVg-VlFg-Fl.

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In this problem you will investigate the behavior of a van der Waals fluid near the critical point. It is easiest to work in terms of reduced variables throughout.

(a) Expand the van der Waals equation in a Taylor series in , keeping terms through order . Argue that, for T sufficiently close to Tc, the term quadratic in (V-VC)becomes negligible compared to the others and may be dropped.

(b) The resulting expression for P(V) is antisymmetric about the point V = Ve. Use this fact to find an approximate formula for the vapor pressure as a function of temperature. (You may find it helpful to plot the isotherm.) Evaluate the slope of the phase boundary,dP/dT

( c) Still working in the same limit, find an expression for the difference in volume between the gas and liquid phases at the vapor pressure. You should find Vg-VlTc-Tβ.8, where (3 is known as a critical exponent. Experiments show that (3 has a universal value of about 1/3, but the van der Waals model predicts a larger value.

(d) Use the previous result to calculate the predicted latent heat of the transformation as a function of temperature, and sketch this function.

The shape of the T = Tc isotherm defines another critical exponent, called P-PcV-VcδCalculate 5 in the van der Waals model. (Experimental values of 5 are typically around 4 or 5.)

A third critical exponent describes the temperature dependence of the isothermal compressibility, K=-t This quantity diverges at the critical point, in proportion to a power of (T-Tc) that in principle could differ depending on whether one approaches the critical point from above or below. Therefore the critical exponents 'Y and -y' are defined by the relations

κT-Tc-γTc-T-γ'

Calculate K on both sides of the critical point in the van der Waals model, and show that 'Y = -y' in this model.

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