Write down the equilibrium condition for each of the following reactions:

(a)2HH2(b)2CO+O22CO2(c)CH4+2O22H2O+CO2(d)H2SO42H++SO42-(e)2p+2nHe4

Short Answer

Expert verified

Hence, the equilibrium condition for each reaction is given.

Step by step solution

01

Given information

We have the following reactions:

(a)2HH2(b)2CO+O22CO2(c)CH4+2O22H2O+CO2(d)H2SO42H++SO42-(e)2p+2nHe4

02

Explanation

(a) For the first reaction, the equilibrium condition is:

2μH=2μH2

(b) For the second reaction, the equilibrium condition is:

2μCO+μO2=2μCO2

(c) For the third reaction, the equilibrium condition is:

μCH4+2μO2=2μH2O+μCO2

(d) For the fourth reaction, the equilibrium condition is:

μH2SO4=2μH++μH2SO4

(e) For the fifth reaction, the equilibrium condition is:

2μp+2μn=4μHe

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