In the text I showed that for an Einstein solid with three oscillators and three units of energy, the chemical potential is μ=-ϵ(where ϵis the size of an energy unit and we treat each oscillator as a "particle"). Suppose instead that the solid has three oscillators and four units of energy. How does the chemical potential then compare to -ϵ ? (Don't try to get an actual value for the chemical potential; just explain whether it is more or less than -ϵ.)

Short Answer

Expert verified

μ<-

Step by step solution

01

Explanation of Solution

Given:

For N=3and q=3the chemical potential is μ=-

02

Calculation

The chemical potential formula is

μ=ΔUΔNS

The entropy for N=3and q=3is

S=klnΩ

S=klnN+q-1|q-1|q3+3-1

S=kln|3-1|35¯

S=kln|2|3|2||2|

S=kln(10)

The entropy must be constant throughout.

The entropy for N=3and q=4is,

S=klnΩS=klnN+q1|q1|q3+31S=kln|31|35_S=kln|2|3|2||2|S=kln(10)

Thus, the entropy increases so to reduce the entropy to its original value.

03

Conclusion 

The chemical potential is lowered.

μ<-

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Most popular questions from this chapter

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