Consider an Einstein solid for which both N and q are much greater than 1. Think of each oscillator as a separate "particle."

(a) Show that the chemical potential is

role="math" localid="1646995468663" μ=-kTlnN+qN

(b) Discuss this result in the limits Nqand Nq, concentrating on the question of how much Sincreases when another particle carrying no energy is added to the system. Does the formula make intuitive sense?

Short Answer

Expert verified

(a) It is proved that the chemical potential is μ=-kTlnN+qN

(b) When N>>qthere are more oscillation than energy quanta, so the multiplicity is about the same.

When N<<qthere are more quanta than oscillator so there is more possible microstate. So, the multiplicity and the entropy increases.

Step by step solution

01

Part (a) Step 1 : Given Information

Number of oscillations, N>>1

Number of units of energy,q>>1

02

Part (a) Step 2 : Calculation

The multiplicity is

Ω=N2πq(N+q)q+Nqqq+NNNΩq+Nqqq+NNN

The entropy is

S=k[(q+N)ln(q+N)-qlnq-NlnN]

The chemical potential is

μ=TSNU.Vμ=TkN[(q+N)ln(q+N)qlnqNlnN]μ=kTlnq+NN

03

Part (a) Step 3 : Conclusion

The chemical potential is,

μ=-kTlnq+NN

04

Part (b) Step 1 : Given Information

N>>qN<<qU=0

05

Part (b) Step 2 : Calculation

At N>>q, the chemical potential is,

μ-kTln1+qN

At Nq, the chemical potential is,

μkTlnqNμ

06

Part (b) Step 3 : Conclusion

When N>>qthere are more oscillation than energy quanta, so the multiplicity is about the same. When N<<qthere are more quanta than oscillator so there is more possible microstate. So, the multiplicity and the entropy increases.

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Most popular questions from this chapter

Starting with the result of Problem 2.17, find a formula for the temperature of an Einstein solid in the limit qN. Solve for the energy as a function of temperature to obtain U=Nϵe-ϵ/kT (whereϵ is the size of an energy unit).

A liter of air, initially at room temperature and atmospheric pressure, is heated at constant pressure until it doubles in volume. Calculate the increase in its entropy during this process.

Use a computer to reproduce Table 3.2 and the associated graphs of entropy, temperature, heat capacity, and magnetization. (The graphs in this section are actually drawn from the analytic formulas derived below, so your numerical graphs won't be quite as smooth.)

Consider a monatomic ideal gas that lives at a height z above sea level, so each molecule has potential energy mgzin addition to its kinetic energy.

(a) Show that the chemical potential is the same as if the gas were at sea level, plus an additional term mgz:

μ(z)=-kTlnVN2πmkTh23/2+mgz.

(You can derive this result from either the definition μ=-T(S/N)U,Vor the formula μ=(U/N)S,V.

(b) Suppose you have two chunks of helium gas, one at sea level and one at height z, each having the same temperature and volume. Assuming that they are in diffusive equilibrium, show that the number of molecules in the higher chunk is

N(z)=N(0)e-mgz/kT

in agreement with the result of Problem 1.16.

In Section 2.5 I quoted a theorem on the multiplicity of any system with only quadratic degrees of freedom: In the high-temperature limit where the number of units of energy is much larger than the number of degrees of freedom, the multiplicity of any such system is proportional to UNf/2, whereNf is the total number of degrees of freedom. Find an expression for the energy of such a system in terms of its temperature, and comment on the result. How can you tell that this formula forΩ cannot be valid when the total energy is very small?

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