Prove that the peak of the Planck spectrum is at x = 2.82.

Short Answer

Expert verified

Hence proved that plank's spectrum is at x = 2.82.

Step by step solution

01

Given information

The peak of the Planck spectrum is at e = 2.82.

02

Explanation

Set the derivative of x3/ex-1with respect to x equals to zero to get the maximum, then solve for:

xx3ex-1=03x2ex-1-x3exex-12=03x2ex-1-x3ex=03x2ex-3x2-x3ex=03ex-3-xex=0

Using matlab to solve the above equation: The code is:

Therefore,x=2.8214

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Most popular questions from this chapter

An atomic nucleus can be crudely modeled as a gas of nucleons with a number density of 0.18fm-3(where 1fm=10-15m). Because nucleons come in two different types (protons and neutrons), each with spin 1/2, each spatial wavefunction can hold four nucleons. Calculate the Fermi energy of this system, in MeV. Also calculate the Fermi temperature, and comment on the result.

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