Starting from equation 7.83, derive a formula for the density of states of a photon gas (or any other gas of ultra relativistic particles having two polarisation states). Sketch this function.

Short Answer

Expert verified

Hence, the formula for density of states of a photon gas isg(ϵ)=8πVϵ2(hc)3

Step by step solution

01

Given information

The equation 7.83 is

UV=8π(hc)30ϵ3eϵ/kT-1dϵ

02

Explanation

The equation 7.83 is:

UV=8π(hc)30ϵ3eϵ/kT-1dϵ

We can write the equation as:

localid="1647752992962">U=0ϵ8πVϵ2(hc)31eϵ/kT-1dϵ(1)

Distribution function for Planck's constant is given as:

n¯Pl=1eϵ/kT-1

Substituting this into (1)

U=0ϵ8πVϵ2(hc)3n¯Pldϵ

Hence the energy density for Planck's constant is

g(ϵ)=8πVϵ2(hc)3

Using Python to solve this function, the code is:

The graph is:

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