In Section 6.5 I derived the useful relation F=-kTln(Z)between the Helmholtz free energy and the ordinary partition function. Use analogous argument to prove that ϕ=-kT×ln(Z^), where Z^ is the grand partition function and ϕis the grand free energy introduced in Problem 5.23.

Short Answer

Expert verified

The grand canonical function is ϕ=-kT×ln(Z^) which is proved successfully.

Step by step solution

01

Step 1. Grand Potential differentiate

Formula for grand potential is:

ϕ=U-TS-μN

ϕ=U-TS-μN

where, Sis entropy, Tis temperature, Nis particles number and μis Gibbs free energy per particle.

Use thermodynamic equation:

dU=TdS-PdV+μdN

Equation for an infinitesimal change in grand potential is:

dϕ=d(U-TS-μN)=dU-d(TS)-d(μN)=dU-TdS-SdT-μdN-Ndμ

Substitute dU=TdS-PdV+μdN

localid="1647239388505" dϕ=TdS-PdV+μdN-TdS-SdT-μdN-Ndμ=-SdT-PdV-Ndμ

Differentiate equation dϕ=-SdT-PdV-Ndμwith respect to μ

ϕμTV=-N

02

Step 2. Number of particles equation

We differentiate function ϕ~=-kT×ln(Z)^ with respect to μ.

ϕ~μTV=-kTZ^Z^μ

Here, Z^ is grand partition function.

As, average number of particles is given by:

localid="1647240173822" N¯=kTZ^Z^μ

Substitute kTZ^Z^μ=N¯ in above differential equation,

ϕ~μTV=-N¯

03

Step 3. Canonical function equation

For grand canonical function ϕandϕ~at μ=0we get,

ϕ~=-kT×ln(Z)=F

Here, F=-kT×ln(Z)is called Helmholtz free energy.

Substitute μ=0in equation ϕ=U-TS-μN

ϕ=U-TS

As, Helmholtz free energy is F=U-TS

Substitute F=U-TSin equation ϕ=U-TSwe get,

ϕ=F

So, ϕand ϕ~at same initial conditions have same values. Therefore, they are the same functions. Hence, the grand canonical function is ϕ=-kT×ln(Z^).

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