Use a pocket calculator to check the accuracy of Stirling's approximation forN=50 . Also check the accuracy of equation 2.16forlnN! .

Short Answer

Expert verified

By using pocket calculator as,

50!=3.0414×1064;ln(50!)=148.4778and

By using Stirling's approximation as,

50!3.0363×1064,;ln(50!)145.6012.

Step by step solution

01

Step: 1 Using pocket calculator:

By using pocket calculator n=50as

N!=50!=3.0414×1064ln(N!)=ln(50!)=148.4778

We have,

N!=50!50(50e502π50N!=3.0363×106450!3.0363×1064.

02

Step: 2 Using Stirling's approximation:

By using Stirling's approximation as,

N!NNeN2πNln(N!)Nln(N)N

We have,

ln(N!)=ln(50!)50ln(50)50ln(N!)=145.6012ln(50!)145.6012

The Stirling's approximation is applicable for evenn=50.

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