Suppose you have a Cassegrain telescope at home, with a \(0.25 \mathrm{m}\) diameter primary mirror and a secondary mirror with a diameter of \(5 \mathrm{cm} .\) What fraction of the primary is blocked by the secondary?

Short Answer

Expert verified
4.1% of the primary mirror is blocked by the secondary mirror.

Step by step solution

01

Find the areas of both mirrors

First, calculate the area of the primary and secondary mirror using the formula for the area of a circle \[ A = \frac{\text{πd}^2}{4} \] where d is the diameter.
02

Calculate the primary mirror's area

For the primary mirror, d = 0.25 m. Substitute this into the area formula: \[ A_{\text{primary}} = \frac{π \times (0.25 \text{ m})^2}{4} = \frac{π \times 0.0625 \text{ m}^2}{4} = 0.049 \text{ m}^2 \]
03

Calculate the secondary mirror's area

For the secondary mirror, d = 0.05 m. Substitute this into the area formula: \[ A_{\text{secondary}} = \frac{π \times (0.05 \text{ m})^2}{4} = \frac{π \times 0.0025 \text{ m}^2}{4} = 0.002 \text{ m}^2 \]
04

Find the fraction blocked by the secondary mirror

Divide the area of the secondary mirror by the area of the primary mirror to find the fraction blocked: \[ \text{Fraction blocked} = \frac{A_{\text{secondary}}}{A_{\text{primary}}} = \frac{0.002 \text{ m}^2}{0.049 \text{ m}^2} \]
05

Simplify the fraction

Simplify the fraction to find the final answer: \[ \text{Fraction blocked} = 0.041 = 4.1\text{ %} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Telescope Design
A Cassegrain telescope is a popular optical telescope design, well-known for its compact structure and effective light-gathering capabilities. This type of telescope uses a combination of a large primary mirror and a smaller secondary mirror to focus light. The primary mirror is parabolic, while the secondary mirror is hyperbolic.
The light enters through the open end, reflects off the primary mirror, converges towards the secondary mirror, and finally, passes through a hole in the primary mirror to the eyepiece or camera.
The main advantage of the Cassegrain design is the capacity to fit a long focal length system into a relatively short length, making them ideal for both amateur astronomers and professionals who need portable telescopes.
Mirror Area Calculation
Calculating the area of the mirrors in a Cassegrain telescope involves using the formula for the area of a circle: \( A = \frac{\pi d^2}{4} \). Here, 'd' represents the diameter of the mirror.

Example:
For the primary mirror with a diameter of 0.25 meters, we substitute into the formula:
\[ A_{\text{primary}} = \frac{\pi \times (0.25 \text{ m})^2}{4} = \frac{\pi \times 0.0625 \text{ m}^2}{4} = 0.049 \text{ m}^2 \]
Similarly, for the secondary mirror with a diameter of 0.05 meters:
\[ A_{\text{secondary}} = \frac{\pi \times (0.05 \text{ m})^2}{4} = \frac{\pi \times 0.0025 \text{ m}^2}{4} = 0.002 \text{ m}^2 \]
The area calculations allow us to understand how much light each mirror can capture, vital for determining the telescope's efficiency.
Fractional Blockage
In a Cassegrain telescope, the secondary mirror obstructs part of the primary mirror, reducing the overall light-gathering capability. To calculate the fractional blockage, you divide the area of the secondary mirror by the area of the primary mirror:
\[ \text{Fraction blocked} = \frac{A_{\text{secondary}}}{A_{\text{primary}}} = \frac{0.002 \text{ m}^2}{0.049 \text{ m}^2} \]
This gives:
\[ \text{Fraction blocked} = 0.041 \]
This means the secondary mirror blocks 4.1% of the primary mirror's area. While this might seem significant, modern telescope designs minimize this blockage to retain as much light-gathering efficiency as possible.
Despite the blockage, Cassegrain telescopes still perform exceptionally well due to their optimized design allowing for high-quality observations.
Optical Telescopes
Optical telescopes, like the Cassegrain, are instruments that collect and magnify light from celestial objects to make them visible. They use lenses or mirrors to focus light into an image.
  • Refracting Telescopes: Use lenses to bend light to a focus point.
  • Reflecting Telescopes: Use mirrors to reflect light to a focus point.
  • Catadioptric Telescopes: Combine lenses and mirrors for light focusing.
The Cassegrain telescope falls under the reflecting telescope category but also has a secondary mirror, making it a bit of a hybrid.
Larger mirrors in optical telescopes allow for better light-gathering power, leading to clearer, more detailed images of distant astronomical objects. The specific optical design and quality of the mirrors and lenses also play crucial roles in the performance of these telescopes.

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Most popular questions from this chapter

(a) Using the fact that the limiting magnitude of the eye is \(6,\) derive an expression for the limiting magnitude for direct viewing with a telescope of diameter \(D\). (Ignore the effects of sky brightness.) (b) Use this result to derive an expression for the farthest distance at which a telescope of diameter \(D\) can be used to see an object of absolute magnitude \(M\).

The sodium D lines in the Sun's spectrum are at wavelengths of 589.594 and \(588.997 \mathrm{nm}\) (a) If a grating has \(10^{4}\) lines/cm, how wide must the grating be to resolve the two lines in first order? (b) Under these conditions what is the angular separation between the two lines? (c) How would the results in (a) and (b) change for second order?

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The full Moon subtends an angle of approximately 30 arc min. How large would the image of the Moon be on your film if you used a \(500 \mathrm{mm}\) focal length lens for your camera?

Suppose we are observing an infrared source that is 500 pc away. It radiates like a \(50 \mathrm{K}\) blackbody and is 1 pc in extent. (a) What is the total energy per second per square meter reaching the Earth from this source? How does that compare with the total amount of solar radiation reaching the Earth per second per square meter. (b) Suppose we observe this source using a satellite with a \(1 \mathrm{m}\) diameter mirror, and we observe at a wavelength of \(100 \mu \mathrm{m} .\) What is the energy/s/Hz striking the telescope? (c) Suppose the telescope radiates like a blackbody at \(300 \mathrm{K}\), but with an efficiency of \(1 \% .\) (That is, the spectrum looks like that of a blackbody but with an intensity reduced by a factor of \(100 .\). What is the energy/Hz/s given off by the telescope at this wavelength? How does your answer compare with that in (b). (d) Redo part (c), assuming that we can cool the mirror to \(30 \mathrm{K}\) (still with a \(1 \%\) emission efficiency

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