Chapter 21: Q18PE (page 775)

What is the internal resistance of an automobile battery that has an emf of $12.0 V$ and a terminal voltage of $15.0 V$ while a current of $8.00 A$ is charging it?

Short Answer

Expert verified

The internal resistance is $0.375 Ω$ .

Step by step solution

Terminal voltage

The terminal voltage of the cell is

$V = emf - lR$

Here, emf is the output voltage of the battery, $I$ is the current and $R$ is the resistance.

Calculation of the internal resistance

Given value of the EMF is E=12.0 V

Current is $l = 8.00 A$

Terminal voltage, $V = 15.0 V$ .

When charging , $E = V - lr$ .

So internal, resistance

role="math" localid="1656141444437" $l = \frac{V - E}{r} = \frac{15.0 V - 12.0 V}{8.00 A} = 0.375 Ω$

Therefore, the internal resistance is $0.375 Ω$ .

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What is the internal resistance of an automobile battery that has an emf of $12.0 V$ and a terminal voltage of $15.0 V$ while a current of $8.00 A$ is charging it?

Short Answer

Step by step solution

Terminal voltage

Calculation of the internal resistance

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What is the internal resistance of an automobile battery that has an emf of 12.0Vand a terminal voltage of 15.0Vwhile a current of 8.00Ais charging it?

Short Answer

Step by step solution

Terminal voltage

Calculation of the internal resistance

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Atoms and Radioactivity

Conservation of Energy and Momentum

Particle Model of Matter

Geometrical and Physical Optics

Nuclear Physics

Linear Momentum

Study anywhere. Anytime. Across all devices.

What is the internal resistance of an automobile battery that has an emf of $12.0 V$ and a terminal voltage of $15.0 V$ while a current of $8.00 A$ is charging it?