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Chapter 21: Q35PE (page 776)

Apply the junction rule at point a in Figure 21.52.

Short Answer

Expert verified

Using the junction rule on point 'a', we obtained:

I3=I2+I1

Step by step solution

01

Definition of Kirchhoff's law

Kirchhoff's first law defines currents at circuit junctions. It states that the sum of currents flowing into and out of a junction in an electrical circuit equals the sum of currents flowing out of the junction.

02

Explanation for the junction rule

The sum of currents entering the junction equals the sum of currents leaving the junction, according to the junction rule. An equation may be written for point an in the figure 21.55 using the following rule:

I3=I2+I1

Hence current at location 'a' can be calculated using Kirchhoff's Junction rule as follows:

I3=I2+I1

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Most popular questions from this chapter

Consider a camera's flash unit. Construct a problem in which you calculate the size of the capacitor that stores energy for the flash lamp. Among the things to be considered are the voltage applied to the capacitor, the energy needed in the flash and the associated charge needed on the capacitor, the resistance of the flash lamp during discharge, and the desired \(RC\) time constant.

Why should you not connect an ammeter directly across a voltage source as shown in Figure21.48?(Note that script Ein the figure stands for emf.)

Is every emf a potential difference? Is every potential difference an emf? Explain.

A car battery with a 12-V emf and an internal resistance of 0.050Ωis being charged with a current of 60 A Note that in this process the battery is being charged. (a) What is the potential difference across its terminals? (b) At what rate is thermal energy being dissipated in the battery? (c) At what rate is electric energy being converted to chemical energy? (d) What are the answers to (a) and (b) when the battery is used to supply 60 A to the starter motor?

Apply the loop rule to loop \({\rm{afedcba}}\) in Figure \({\rm{21}}{\rm{.47}}\)
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