Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 21: Q9CQ (page 771)

If two household lightbulbs rated 60W and 100W are connected in series to household power, which will be brighter? Explain.

Short Answer

Expert verified

In series to household power, 60W bulb will be brighter.

Step by step solution

01

Definition of voltage

The energy usage rate of one joule every sec is described as one watt.

02

Finding which bulb will be brighter

A bulb's resistance is inversely proportional to its power rating. That is, the higher the power rating, the lower the resistance. The resistance of the bulb is directly proportional to the bulb's power or brightness in series.A bulb's resistance is inversely proportional to its power rating. As a result, the resistance of a 60-watt bulb is higher than that of a 100watt bulb.

The resistance of the bulb is directly proportional to the bulb's power or brightness in series. As a result, the brightness of a 60W bulb will be higher due to its higher resistance.

Therefore, it will be brighter with a 60W bulb.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Referring to Figure 21.6, (a) CalculateP3and note how it compares withP3found in the first two example problems in this module. (b) Find the total power supplied by the source and compare it with the sum of the powers dissipated by the resistors.

Figure 21.55 shows how a bleeder resistor is used to discharge a capacitor after an electronic device is shut off, allowing a person to work on the electronics with less risk of shock. (a) What is the time constant? (b) How long will it take to reduce the voltage on the capacitor to 0.250%(5% of 5%) of its full value once discharge begins? (c) If the capacitor is charged to a voltage V0 through a 100-Ω resistance, calculate the time it takes to rise to 0.865V0 (This is about two-time constants.)

Show that if two resistors R1and R2are combined and one is much greater than the other (R1>>R2): (a) Their series resistance is very nearly equal to the greater resistance R1(b) Their parallel resistance is very nearly equal to smaller resistanceR2 .

A0.0200Ωammeter is placed in series with a10.00‐Ωresistor in a circuit. (a) Draw a circuit diagram of the connection. (b) Calculate the resistance of the combination. (c) If the voltage is kept the same across the combination as it was through the10.00‐Ωresistor alone, what is the percent decrease in current? (d) If the current is kept the same through the combination as it was through the10.00‐Ωresistor alone, what is the percent increase in voltage? (e) Are the changes found in parts (c) and (d) significant? Discuss.

Standard automobile batteries have six lead-acid cells in series, creating a total emf of 12.0 V. What is the emf of an individual lead-acid cell?
See all solutions

Recommended explanations on Physics Textbooks

Medical Physics

Read Explanation

Fields in Physics

Read Explanation

Astrophysics

Read Explanation

Physical Quantities And Units

Read Explanation

Linear Momentum

Read Explanation

Physics of Motion

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free