If the acceleration of a system is zero, are no external forces acting on it? What about internal forces? Explain your answers.

Short Answer

Expert verified

The sum of the external forces acting on a system will be zero when the acceleration of the system is zero. The internal forces on a system do not depend on whether a system is under acceleration or not.

Step by step solution

01

Concept of Newton’s second law of motion

Newton’s second law of motion states that the acceleration of a system is directly proportional to the net external force acting on the system and is inversely proportional to the mass of the system. Mathematically,

Fnet=ma

HereFnetis the net force,mis the mass, andais the acceleration.

02

Explanation for a system with no external forces has zero acceleration

The sum of the external forces acting on a system will be zero when the acceleration of the system is zero. This does not mean that there are no external forces acting on it, but the sum of all the external forces acting on it must be zero.

The internal forces on a system do not depend on whether a system is under acceleration or not. An internal force is considered when any part of a system exerts a certain force on another part of the same system.

According to Newton's Third Law of Motion, the other part of the system exerts an equal and opposite force on that part. Since they are equal and opposite forces, they cancel each other, and hence the net force is zero.

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Most popular questions from this chapter

Consider two people pushing a toboggan with four children on it up a snow-covered slope. Construct a problem in which you calculate the acceleration of the toboggan and its load. Include a free-body diagram of the appropriate system of interest as the basis for your analysis. Show vector forces and their components and explain the choice of coordinates. Among the things to be considered are the forces exerted by those pushing, the angle of the slope, and the masses of the toboggan and children.

Suppose your car was mired deeply in the mud, and you wanted to use the method illustrated in Figure 4.37 to pull it out.

(a) What force would you have to exert perpendicular to the center of the rope to produce a force of 12,000 N on the car if the angle is 2.00°? In this part, explicitly show how you follow the steps in the Problem-Solving Strategy for Newton’s laws of motion.

(b) Real ropes stretch under such forces. What force would be exerted on the car if the angle increases to 7.00° and you still apply the force found in part (a) to its center?

Explain, in terms of the properties of the four basic forces, why people notice the gravitational force acting on their bodies if it is such a comparatively weak force.

Since astronauts in orbit are apparently weightless, a clever method of measuring their masses is needed to monitor their mass gains or losses to adjust diets. One way to do this is to exert a known force on an astronaut and measure the acceleration produced. Suppose a net external force of 50.0 N is exerted and the astronaut’s acceleration is measured to be 0.893 m/s2.

(a) Calculate her mass.

(b) By exerting a force on the astronaut, the vehicle in which they orbit experiences an equal and opposite force. Discuss how this would affect the measurement of the astronaut’s acceleration. Propose a method in which recoil of the vehicle is avoided.

A rock is thrown straight up. What is the net external force acting on the rock when it is at the top of its trajectory?

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