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Chapter 18: Q22CQ (page 662)

Can the belt of a Van de Graaff accelerator be a conductor? Explain.

Short Answer

Expert verified

No, conductor cannot be used for the construction of belt of Van de Graff generator.

Step by step solution

01

Van de Graaff accelerator

Van de Graaf accelerator or generator is an electrostatic generator that produces hundreds of thousands of volts (DC) at low current levels. It uses a moving belt to accumulate electric charge on a hollow metal dome.

02

Using conductor as a belt of Van de Graaff accelerator

If the belt of the Van de Graaff accelerator is made using a conductor, then all the charges sprayed on the belt will immediately flow to the ground. Hence the charge will not be built on the terminal and it will not give rise to high potential.

Hence, the belt of a Van de Graaff accelerator cannot be a conductor.

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Most popular questions from this chapter

(a) Two point charges totaling\({\bf{8}}.{\bf{00}}{\rm{ }}{\bf{\mu C}}\)exert a repulsive force of\({\bf{0}}.{\bf{150}}{\rm{ }}{\bf{N}}\)on one another when separated by\({\bf{0}}.{\bf{500}}{\rm{ }}{\bf{m}}\). What is the charge on each? (b) What is the charge on each if the force is attractive?

(a) Find the direction and magnitude of an electric field that exerts a\[{\rm{4}}{\rm{.80 \times 1}}{{\rm{0}}^{{\rm{ - 17}}}}{\rm{N}}\]westward force on an electron. (b) What magnitude and direction force does this field exert on a proton?

Suppose a speck of dust in an electrostatic precipitator has 1.0000×1012 protons in it and has a net charge of -5.00 nC (a very large charge for a small speck). How many electrons does it have?

The practical limit to an electric field in air is about\(3.00 \times {10^6}{\rm{ N}}/{\rm{C}}\). Above this strength, sparking takes place because air begins to ionize and charges flow, reducing the field. (a) Calculate the distance a free proton must travel in this field to reach\(3.00\% \)of the speed of light, starting from rest. (b) Is this practical in air, or must it occur in a vacuum?

Point charges of \[{\rm{5}}{\rm{.00 \mu C}}\] and \[{\rm{--3}}{\rm{.00 \mu C}}\] are placed \[{\rm{0}}{\rm{.250 m}}\] apart. (a) Where can a third charge be placed so that the net force on it is zero? (b) What if both charges are positive?
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