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Chapter 20: Q49PE (page 734)

Electrons in an X-ray tube are accelerated through\(1.00 \times {10^2}\;kV\)and directed toward a target to produce X-rays. Calculate the power of the electron beam in this tube if it has a current of 15.0 mA.

Short Answer

Expert verified

The power of the tube is, 150kW.

Step by step solution

01

Definition of Power

The power is defined by the formula

\(P = I\Delta V......(1)\)

Here\(I\)is current and\(\Delta V\)is the potential difference.

02

Information Provided

  • Electrons are accelerated with voltage:\(1.00 \times {10^2}\;kV\)
  • Current in electron beam is: 15mA
03

Calculation of the power

The power of the electron beam in the X-ray tube is found from Equation\((1)\):

\(P = I\Delta V\)

Entering the values for\(I\)and\(\Delta V\):

Therefore, the power of the tube is, 150kW.

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Most popular questions from this chapter

A large cyclotron directs a beam of He++ nuclei onto a target with a beam current of 0.250 mA.

(a) How many He++ nuclei per second is this?

(b) How long does it take for 1.00 C to strike the target?

(c) How long before 1.00 mol of He++ nuclei strike the target?

A charge of \(4.00{\rm{ }}C\) charge passes through a pocket calculator’s solar cells in \(4.00{\rm{ }}h\). What is the power output, given the calculator’s voltage output is \(3.00{\rm{ }}V\)? (See Figure \(20.40\).)

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(a) A defibrillator sends a \({\bf{6}}{\bf{.00}}\;{\bf{A}}\) current through the chest of a patient by applying a \({\bf{10000}}\;{\bf{V}}\) potential as in the figure below. What is the resistance of the path? (b) The defibrillator paddles make contact with the patient through a conducting gel that greatly reduces the path resistance. Discuss the difficulties that would ensue if a larger voltage were used to produce the same current through the patient, but with the path having perhaps 50 times the resistance. (Hint: The current must be about the same, so a higher voltage would imply greater power. Use the equation for power: \({\bf{P = }}{{\bf{I}}^{\bf{2}}}{\bf{R}}\).)

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