Foolishly trying to fish a burning piece of bread from a toaster with a metal butter knife, a man comes into contact with \({\bf{120 V AC}}\). He does not even feel it since, luckily, he is wearing rubber-soled shoes. What is the minimum resistance of the path the current follows through the person?

Ohm’s law states that the ratio of potential difference applied In the circuit\(\left( {\bf{V}} \right)\)to the current flowing in the circuit\(\left( {\bf{I}} \right)\)always remains constant. This constant ratio is known as resistance\(\left( {\bf{R}} \right)\).

\({\bf{R = }}\frac{{\bf{V}}}{{\bf{I}}}\; \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \cdot \left( 1 \right)\)

The AC power source's voltage is:\(V = 120\;{\rm{V}}\)

The sensational threshold is:

\(\begin{array}{c}I = (1.00\;\;{\rm{mA}})\left( {\frac{{1\;\;{\rm{A}}}}{{1000\;\;{\rm{A}}}}} \right)\\ = 1.00 \times {10^{ - 3}}\;{\rm{A}}\end{array}\)

For the given values of\(V\;{\rm{and}}\;I\), equation (1) becomes

\(\begin{array}{c}R = \frac{{120\;{\rm{V}}}}{{1.00 \times {{10}^{ - 3}}\;{\rm{A}}}}\\ = 1.20 \times {10^5}\;\Omega \end{array}\)

Therefore, the least resistance of the current's course through the individual is \(1.20 \times {10^5}\;\Omega \)