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Chapter 19: Q25PE (page 697)

What is the potential 0.530×10-10mfrom a proton (the average distance between the proton and electron in a hydrogen atom)?

Short Answer

Expert verified

The potential at 0.530×10-10mfrom a proton is V=27.2V.

Step by step solution

01

Given Data

Distance from proton is0.530×10-10m

02

Concept Introduction

Electric Potential Due to a Single Charge: To determine the electric potential V due to a single source charge Q at a specific location, place a test charge qat that location and determine the electric potential energy UQqof a system containing the test charge and the source charge that creates the field. The electric potential is given as–

V=UQqq=kQr...........................(1)

Where k=8.99×109N·m2/Cis a proportionality constant called Coulomb's constant.

03

Calculation for Electric Potential

The electric potential a distance r from the proton is found from Equation (1) –

V=kqr

Entering the values for k, q, and r–

V=(8.99×109N×m2/C)(1.60×10-19C)0.530×10-10m=27.2V

Therefore, the potential is obtained as V=27.2V.

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Most popular questions from this chapter

Find the ratio of speeds of an electron and a negative hydrogen ion (one having an extra electron) accelerated through the same voltage, assuming non-relativistic final speeds. Take the mass of the hydrogen ion to be \(1.67 \times {10^{ - 27}}{\rm{ }}kg\).

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