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Chapter 19: Q48PE (page 698)

What charge is stored in the capacitor in Example 19.8?

Short Answer

Expert verified

The amount of charge stored in a capacitor when 3.00×103V is applied to it, is Q=26.6μC .

Step by step solution

01

Given data

Area of plates (A) = 1.00 m2

Separation between plates (d) = 1.00 mm

Voltage between the plates (V) = 3.00 x 103V

02

Concept Introduction

The ability of any capacitor to store energy in the form of electric field is known as Capacitance. The capacitanceC is given as –

C=QΔV.....................(1)

Here Q is the charge accumulated at the plates and ∆Vis the potential difference between the plates.

03

Calculation for Charge Stored

The charge stored in the capacitor is found by solving Equation (1) for Q –

Q=C×ΔV

Entering the values for C and ∆V, it is obtained –

Q=(8.85×10-9F)(3.00×103V)=26.6×10-6C=(26.6×10-6C)(106μC1C)=26.6μC

Therefore, the charge stored is Q=26.6μC.

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Most popular questions from this chapter

What is the relationship between voltage and energy? More precisely, what is the relationship between potential difference and electric potential energy?

The naturally occurring charge on the ground on a fine day out in the open country is \( - 1.00n{\rm{ }}C/{m^2}\).

(a) What is the electric field relative to ground at a height of \(3.00{\rm{ }}m\)?

(b) Calculate the electric potential at this height.

(c) Sketch electric field and equipotential lines for this scenario.

Find the charge stored when \(5.50{\rm{ }}V\) is applied to an \(8.00{\rm{ }}\mu F\) capacitor.

A165μFcapacitor is used in conjunction with a motor. How much energy is stored in it when 119 Vis applied?

Sketch the equipotential lines a long distance from the charges shown in Figure \({\rm{19}}{\rm{.28}}\). Indicate the direction of increasing potential.
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