Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 19: Q65PE (page 699)

A165μFcapacitor is used in conjunction with a motor. How much energy is stored in it when 119 Vis applied?

Short Answer

Expert verified

The energy stored in the capacitor is 1.17 J.

Step by step solution

01

Definition of Capacitor

The energy stored in a capacitance C capacitor charged to a potential difference ΔVis as follows:

UE=12C(ΔV)2

02

Given information

The capacitor's capacitance is:C=(165μF)(1F106μF)=165×10-6F

The capacitance's potential difference is: ΔV=119V

03

Finding the energy  stored in the capacitor

The amount of energy stored in the capacitor can be found from the equation:

UE=12C(ΔV)2

Now, substitute the values of C and ∆V

We get,

UE=12(165×10-6F)(119V)2=1.17 J

Therefore, the energy stored in the capacitor is 1.17 J.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Which methods of radiation protection were used in the device shown in the first photo in Figure 32.35? Which were used in the situation shown in the second photo?

Figure 32.35 (a)

Figure 32.35(b)

(a) This x-ray fluorescence machine is one of the thousands used in shoe stores to produce images of feet as a check on the fit of shoes. They are unshielded and remain on as long as the feet are in them, producing doses much greater than medical images. Children were fascinated with them. These machines were used in shoe stores until laws preventing such unwarranted radiation exposure were enacted in the 1950s. (credit: Andrew Kuchling ) (b) Now that we know the effects of exposure to radioactive material, safety is a priority. (credit: U.S. Navy)

Integrated Concepts

(a) What is the average power output of a heart defibrillator that dissipates 400Jof energy in 10.0 ms?

(b) Considering the high-power output, why doesn’t the defibrillator produce serious burns?

Can different equipotential lines cross? Explain.

Sketch the equipotential lines in the vicinity of the negatively charged conductor in Figure 19.29. How will these equipotentials look a long distance from the object?

The naturally occurring charge on the ground on a fine day out in the open country is \( - 1.00n{\rm{ }}C/{m^2}\).

(a) What is the electric field relative to ground at a height of \(3.00{\rm{ }}m\)?

(b) Calculate the electric potential at this height.

(c) Sketch electric field and equipotential lines for this scenario.
See all solutions

Recommended explanations on Physics Textbooks

Quantum Physics

Read Explanation

Engineering Physics

Read Explanation

Atoms and Radioactivity

Read Explanation

Dynamics

Read Explanation

Thermodynamics

Read Explanation

Work Energy and Power

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free