The \(4.00{\rm{ }}A\) current through a \(7.50{\rm{ }}mH\) inductor is switched off in \(8.33{\rm{ }}ms\). What is the emf induced opposing this?

Short Answer

Expert verified

The \(4.00{\rm{ }}A\) current through a \(7.50{\rm{ }}mH\) inductor is switched off in \(8.33{\rm{ }}ms\). The emf opposing this is, \(\varepsilon = - 3.6\;V\).

Step by step solution

01

Concept Introduction

A current produced by the creation of voltage (electromotive force) in the presence of a shifting magnetic field is known as electromagnetic induction.

This happens when a conductor is placed in a magnetic field that is moving (using an AC power source) or when a conductor is continuously moving in a magnetic field that is stationary.

02

Information Provided

  • Inductance of the inductor:

\(\begin{array}{c}M = 7.50{\rm{ }}mH = \frac{{7.50}}{{1000}}\\ = 0.0075{\rm{ }}H\end{array}\).

  • Current through an inductor:\(4.00{\rm{ }}A\).
  • Time in which current is switched off:

\(\begin{array}{c}t = 8.33{\rm{ }}ms = \frac{{8.33}}{{1000}}\\ = 0.00833{\rm{ }}s\end{array}\).

03

Calculation for the voltage

The formula for the induced electromotive force is –

\(\varepsilon = - M\frac{{\Delta I}}{{\Delta t}}\)

After substituting the values, the calculation is –

\(\begin{array}{c}\varepsilon = - 0.0075 \cdot \frac{4}{{0.00833}}\\ = - 3.6\;V\end{array}\)

Therefore, the value for emf is obtained as \(\varepsilon = - 3.6\;V\).

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Most popular questions from this chapter

(a) A jet airplane with a 75.0 mwingspan is flying at 280 m /s. What emf is induced between wingtips if the vertical component of the Earth’s field is3.00×10-5T? (b) Is an emf of this magnitude likely to have any consequences? Explain.

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What is the peak emf generated by rotating a 1000-turn, \({\rm{5}}{\rm{.00 \times 1}}{{\rm{0}}^{{\rm{ - 5}}}}{\rm{ T}}\) diameter coil in the Earth’s magnetic field, given the plane of the coil is originally perpendicular to the Earth’s field and is rotated to be parallel to the field in \({\rm{10}}{\rm{.0 ms}}\)?

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