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Chapter 23: Q69PE (page 863)

If you want a characteristic RL time constant of 1.00 s, and you have a resistor 500Ω, what value of self-inductance is needed?

Short Answer

Expert verified

The value of self-inductance is 500 H

Step by step solution

01

Given Data

The time constant of the RL circuit is τ=1.00s

The value of resistance isR=500Ω

02

Concept Introduction

The trait of a current-carrying coil that resists or opposes the change in current flowing through it is known as self-inductance. This is mostly owing to the self-induced emf generated by the coil.

03

Calculating the Value of Self-Inductance

In RL circuits, the time constant,τ, can be expressed as,

τ=LR…………….(1)

Rearrange equation (1) for the self-inductance and the substitute the given data, such that

L=τRL=(1.00s)×500Ω=500H

Therefore, the self-inductance is 500 H

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Most popular questions from this chapter

The335 kV AC electricity from a power transmission line is fed into the primary coil of a transformer. The ratio of the number of turns in the secondary to the number in the primary isNS/Np=1000. (a) What voltage is induced in the secondary? (b) What is unreasonable about this result? (c) Which assumption or premise is responsible?

(a) Find the current through a\(0.500{\rm{ }}H\)inductor connected to a\(60.0{\rm{ }}Hz,{\rm{ }}480{\rm{ }}V\)AC source. (b) What would the current be at\(100{\rm{ }}kHz\)?

An RLC series circuit has a \(1.00\;k\Omega \) resistor, a \(150\;\mu H\) inductor, and a \(25.0\;nF\) capacitor. (a) Find the power factor at \(f = 7.50\;Hz\). (b) What is the phase angle at this frequency? (c) What is the average power at this frequency? (d) Find the average power at the circuit's resonant frequency.

Referring to Example 23.14, find the average power at \({\rm{10}}{\rm{.0}}\;{\rm{kHz}}\).

What capacitance should be used to produce a\(2.00\,{\rm{M\Omega }}\)reactance at\(60.0\,{\rm{Hz}}\)?
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