What is the maximum electric field strength in an electromagnetic wave that has a maximum magnetic field strength of \(5.00 \times {10^{ - 4}}\;T\) (about \(10\) times the Earth's)?

Short Answer

Expert verified

The maximum electric field strength value is obtained as \(15 \times {10^4}\;V/m\).

Step by step solution

01

Definition of electromagnetic wave

Examples of waves transmitted by concurrent periodic changes in the strength of the electric and magnetic fields include radio waves, infrared, visible light, ultraviolet, X-rays, and gamma rays.

02

Given Information

  • The magnetic field strength: \(5.00 \times {10^{ - 4}}\;T\)
03

Find the maximum electric field strength in an electromagnetic wave

The formula for calculating the strength of an electric and magnetic field is:

\(E = Bc\)

Here\(E = \)Electric field,\(C = \)speed of light,\(B = \)Magnetic field

Now we must enter the value of\(B\)as it appears in the question,\(c = 3.00 \times {10^8}\;m{s^{ - 1}}\)

\(\begin{aligned} E{\rm{ }} &= Bc\\ &= \left( {5.00 \times {{10}^{ - 4}}T} \right)\left( {3.00 \times {{10}^8}\;m{s^{ - 1}}} \right)\\ &= 15 \times {10^4}\left( {\;V.s/{m^2}} \right)\left( {m{s^{ - 1}}} \right)\\ &= 15 \times {10^4}\;V/m\end{aligned}\)

As a result, the electric field strength is\(E = 15 \times {10^4}\;V/m\).

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