Calculate the average pressure exerted on the palm of a shot-putter’s hand by the shot if the area of contact is ${\text{50.0 cm}}^{\text{2}}$and he exerts a force ofrole="math" localid="1668682357057" $800N$on it. Express the pressure inand compare it with the$1.00\times {10}^{6}Pa$pressures sometimes encountered in the skeletal system.

Fluid statics, often known as hydrostatics, is a branch of fluid mechanics that investigates the state of balance of a floating and submerged body, as well as the pressure in a fluid, or imposed by a fluid, on an immersed body.

The pressure is the rate of force applied to the surface per unit area.

The Force which is given by the hand of shot-putter to the shot-put is$F=800N$.

The area of the contact in meter square is $A=0.005m^2$.

Since they are equivalent, we can write the above equation as:

$$\begin{gathered} P=\frac{F}{A} \\ =\frac{800}{0.005} \\ =160000 \text{Pa} \end{gathered}$$

The Pressure exerted on shot-put is: $1.6\times {10}^{5}Pa$.

Relation of the pressure in $1\times {10}^{6}Pa$.

As we know $1N/m^2=1Pa$.

Hence, we need to do ratio to compare this both quantity

$$\begin{gathered} Ratio=\frac{1.6\times {10}^5}{1\times {10}^6} \\ =0.16 \end{gathered}$$

Therefore, the ratio of the two value is $0.16$.