What fluid is in the device shown in Figure\[{\rm{11}}{\rm{.29}}\]if the force is\[{\rm{3}}{\rm{.16 \times 1}}{{\rm{0}}^{{\rm{ - 3}}}}{\rm{ N}}\]and the length of the wire is\[{\rm{2}}{\rm{.50 cm}}\]? Calculate the surface tension γand find a likely match from Table\[{\rm{11}}{\rm{.3}}\].

Fluid statics, often known as hydrostatics, is a branch of fluid mechanics that investigates the state of balance of a floating and submerged body, as well as the pressure in a fluid, or imposed by a fluid, on an immersed body.

The tensions between molecules that cause a liquid's surface to compress to the lowest feasible surface area.

The force will be equal to the product of surface tension and two times the length of the fluid.

The surface tension of fluid = \[{\rm{? N/m}}\].

The length of the fluid surface is:

\[\begin{array}{c}{\rm{L = 2}}{\rm{.50 cm}}\\{\rm{ = 0}}{\rm{.025 m}}\end{array}\]

The force F exerted due to the surface tension is: \[{\rm{3}}{\rm{.16 \times 1}}{{\rm{0}}^{{\rm{ - 3}}}}{\rm{ N}}\].

Calculating the surface tension as follows:

\(\begin{array}{c}F = 2\sigma L\\\left( {3.16 \times {{10}^{ - 3}}\;{\rm{N}}} \right) = 2\sigma \left( {0.025\;{\rm{m}}} \right)\\\sigma = \frac{{\left( {3.16 \times {{10}^{ - 3}}} \right)}}{{2\left( {0.025} \right)}}\;{\rm{N/m}}\\ = 0.0632\,\;{\rm{N/m}}\end{array}\)

Therefore, surface tension of the fluid is: \[{\rm{0}}{\rm{.0632 N/m}}\]. The fluid is similar to glycerin.