You can chew through very tough objects with your incisors because they exert a large force on the small area of a pointed tooth. What pressure in Pascal can you create by exerting a force of \[{\rm{500 N}}\] with your tooth on an area of \[{\rm{1}}{\rm{.00 m}}{{\rm{m}}^{\rm{2}}}\]?

Short Answer

Expert verified

The Pressure acting on the teeth is obtained as: \[{\rm{5 \times 1}}{{\rm{0}}^{\rm{8}}}{\rm{ Pa}}\].

Step by step solution

01

Conceptual Introduction

Fluid statics, often known as hydrostatics, is a branch of fluid mechanics that investigates the state of balance of a floating and submerged body, as well as the pressure in a fluid, or imposed by a fluid, on an immersed body.

02

Given data

The force per unit perpendicular area across which the force is exerted is known as pressure.

\[P = \frac{F}{A}\]

The surface area creating the pressure is\[{\rm{1 m}}{{\rm{m}}^{\rm{2}}}\].

The surface area creating the pressure in meter square is:

\(\begin{array}{c}A = \frac{1}{{1000000}}\\ = 1 \times {10^{ - 6}}\;\,{{\rm{m}}^2}\end{array}\)

The force acting on the incisor is: \[{\rm{500 N}}\].

03

Pressure acting on the teeth:

By putting all the value into the equation, we get:

\[\begin{array}{c}P = \frac{F}{A}\\ = \frac{{500\;{\rm{N}}}}{{1 \times {{10}^{ - 6}}\;{{\rm{m}}^2}}}\\ = 5 \times {10^8}\;{\rm{Pa}}\end{array}\]

Therefore, pressure acting on the teeth is \[{\rm{5 \times 1}}{{\rm{0}}^{\rm{8}}}{\rm{ Pa}}\], which is huge pressure.

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