An old carpenter’s trick to keep nails from bending when they are pounded into hard materials is to grip the center of the nail firmly with pliers. Why does this help?

Short Answer

Expert verified

Using pliers to hold the nail increases the surface area, which is why the nail stays straight when going into the hard material.

Step by step solution

01

Definition of plier

Two handles on a small tool for pulling, grasping, or cutting are pressed together to merge two specifically formed pieces of metal at the other end.

02

Explaining why nails remains straight

Gripping the center of nail firmly with pliers, increase the moment of inertia. Now, it requires greater amount of force to bend the nail.

Normally when force is applied on the nail, the nail may bend from the straight position. This bending will cause the shear stress on itself. When a plier is employed, the chance of bending is reduced, lowering the risk of shear stress. The nail will remain mostly straight as it enters the hard material.

Moreover, when carpenter holds the nail with pliers, it increases the moment of inertia of system (nail and pliers). Therefore, any bending of the nails will withstand more rigidity. Therefore, holding the pliers provides a precise hole and prevents bending.

Further, gripping of the nail with the pliers increases the surface area. That’s why applied force gets distributed to a larger area. it prevents bending of nails.

x=FSAL

It is clear from the formula that shear deformation is inversely proportional to the surface area. So, if area increases there will be less deformation.

Therefore holding the nail with pliers increase the surface area that’s why nail remains straight while getting into the hard material.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) What is the maximum frictional force in the knee joint of a person who supports 66.0 kgof her mass on that knee?

(b) During strenuous exercise it is possible to exert forces to the joints that are easily ten times greater than the weight being supported. What is the maximum force of friction under such conditions? The frictional forces in joints are relatively small in all circumstances except when the joints deteriorate, such as from injury or arthritis. Increased frictional forces can cause further damage and pain.

Calculate the deceleration of a snow boarder going up a5.0, slope assuming the coefficient of friction for waxed wood on wet snow. The result ofExercise5.1may be useful, but be careful to consider the fact that the snow boarder is going uphill. Explicitly show how you follow the steps inProblem-Solving Strategies.

The glue on a piece of tape can exert forces. Can these forces be a type of simple friction? Explain, considering especially that tape can stick to vertical walls and even to ceilings.

When a glass bottle full of vinegar warms up, both the vinegar and the glass expand, but vinegar expands significantly more with temperature than glass. The bottle will break if it was filled to its tightly capped lid. Explain why, and also explain how a pocket of air above the vinegar would prevent the break. (This is the function of the air above liquids in glass containers.)

Show that the acceleration of any object down an incline where friction behaves simply (that is, where fK=μKN) is a=g{sin(θ)-μKcos(θ)}.Note that the acceleration is independent of mass and reduces to the expression found in the previous problem when friction becomes negligibly small(μK=0 ).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free