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Chapter 29: Q19CQ (page 1061)

Which formula may be used for the momentum of all particles, with or without mass?

Short Answer

Expert verified

De-Broglie’s formula could be used for mass and mass-less particles:

\[{\rm{p = }}\frac{{\rm{h}}}{{\rm{\lambda }}}\]

Step by step solution

01

Formula to describe the momentum of particles

As per De-Broglie's hypothesis which is all microscopic particles, whether mass-less, like photons or having mass, like electrons, have wave properties. Where the relationship between momentum and wavelength is fundamental for all particles. So, we can use this formula to describe the momentum of all particles with or without mass:

\[p = \frac{h}{\lambda }\]

02

De- Broglie’s formula

Where, \[{\rm{p}}\]is the momentum, \[{\rm{h}}\] is Planck's constant and \[{\rm{\lambda }}\] is the wavelength.

Therefore, De-Broglie’s formula could be used for mass and mass-less particles:

\[{\rm{p = }}\frac{{\rm{h}}}{{\rm{\lambda }}}\]

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Most popular questions from this chapter

Question: Violet light of wavelength \[{\rm{400 nm}}\] ejects electrons with a maximum kinetic energy of \[{\rm{0}}{\rm{.860 eV}}\] from sodium metal. What is the binding energy of electrons to sodium metal?

What is the velocity of a 0.400 - kg billiard ball if its wavelength is 7.50 cm (large enough for it to interfere with other billiard balls)?

(a) What is the wavelength of a \(1.00 - eV\) photon?

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(c) Identify the type of EM radiation.

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Question: Photoelectrons from a material with a binding energy of \({\rm{2}}{\rm{.71 eV}}\) are ejected by \({\rm{420 - nm}}\) photons. Once ejected, how long does it take these electrons to travel \({\rm{2}}{\rm{.50 cm}}\) to a detection device?
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