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Chapter 2: Q12PE (page 82)

The speed of propagation of the action potential (an electrical signal) in a nerve cell depends (inversely) on the diameter of the axon (nerve fibre). If the nerve cell connecting the spinal cord to your feet is1.1mlong, and the nerve impulse speed is 18m/s, how long does it take for the nerve signal to travel this distance?

Short Answer

Expert verified

0.0611 m/s

Step by step solution

01

Given Data

  • Speed s=18 m/s
  • Distance d = 1.1 m
02

 Time is taken to pass the impulse

Speed is a scalar quantity, whereas velocity is a vector quantity. Both need magnitude, but only velocity needs direction to express it.

Hence we can use the formula to solve the question:

Time=DistanceSpeed

Substituting the values in the above expression, we get:

T=1.1 m18 m/s=0.0611 s

Hence the time taken by the nerve cell is 0.0611 m/s.

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