Repeat Exercise 22.41 but with the loop lying flat on the ground with its current circulating counterclockwise (when viewed from above) in a location where the Earth's field is north, but at an angle 45°below the horizontal and with a strength of6.00×105T.

Short Answer

Expert verified

(a) Maximum torque on a loop is0.67Nmand direction is west.

(b) The torque is very small so the loop will not have any practical application as a motor.

Step by step solution

01

Definition of torque

Torque, also known as force moment, is the tendency of a force to spin the body to which it is applied in physics.

We can use the equation to determine the torque,

τ=NIABsin(θ) ………….(1)

02

Finding the torque using the formula(a)

Substitute the values in the equation (1), and we get

τ=200×100A×0.79m26.00×105T×sin45°=0.67Nm

Hence, the required maximum torque on a loop is 0.67Nm

Considering direction of force and current we find that the direction of torque is in west.

03

Justification (b)

The torque is very small so the loop will not have any practical application as a motor.

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Most popular questions from this chapter

(a) What is the speed of a supersonic aircraft with a17.0m wingspan, if it experiences a1.60V Hall voltage between its wing tips when in level flight over the north magnetic pole, where the Earth’s field strength is8.00×105T (b) Explain why very little current flows as a result of this Hall voltage.

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Figure22.57shows a long straight wire near a rectangular current loop. What is the direction and magnitude of the total force on the loop?

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Use the right-hand rules to show that the force between the two loops in Figure 22.49 is attractive if the currents are in the same direction and repulsive if they are in opposite directions. Is this consistent with like poles of the loops repelling and unlike poles of the loops attracting? Draw sketches to justify your answers.

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