How far from the starter cable of a car, carrying 150 A, must you be to experience a field less than the Earth’s5.00×10-5T ? Assume a long straight wire carries the current. (In practice, the body of your car shields the dashboard compass.)

Short Answer

Expert verified

Therefore, you must be a distance higher 0.600m .

Step by step solution

01

Definition of magnetic field

A magnetic field is defined as a position in space near a magnet or an electric current where a physical field is formed by a moving electric charge applying force on another moving electric charge.

02

Given information and formula to use

The Earth’s Magnetic field is,B=5.00×10-5T

Current in the wire is,I=150A

Magnetic field due to current carrying wire at a distance r:

B=μoI2ττr………………..(1)

Where μ0is the magnetic permeability of free space.

03

Step 3: The required distance

Rearranging the equation (1) and substituting the given data we will get

B=μ0I2πrr=4π×10-7N/A2×150A2π×5.00×10-5Tr=0.60m

Therefore, you must be a distance higher 0.600m .

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Most popular questions from this chapter

(a) Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.500μC charge and flies due west at a speed of 660 m/s over the Earth’s south magnetic pole, where the 8.00×105Tmagnetic field points straight up. What are the direction and the magnitude of the magnetic force on the plane? (b) Discuss whether the value obtained in part (a) implies this is a significant or negligible effect.

The force per meter between the two wires of a jumper cable being used to start a stalled car is 0.225N/m(a) What is the current in the wires, given they are separated by 2.00cm? (b) Is the force attractive or repulsive?

The force on the rectangular loop of wire in the magnetic field in Figure 22.56 can be used to measure field strength. The field is uniform, and the plane of the loop is perpendicular to the field. (a) What is the direction of the magnetic force on the loop? Justify the claim that the forces on the sides of the loop are equal and opposite, independent of how much of the loop is in the field and do not affect the net force on the loop. (b) If a current of 5.00 A is used, what is the force per tesla on the 20.0-cm-wide loop?


Figure 22.56 A rectangular loop of wire carrying a current is perpendicular to a magnetic field. The field is uniform in the region shown and is zero outside that region.

An electron moving at 4.00×103m/sin a 1.25Tmagnetic field experiences a magnetic force of1.40×1016N. What angle does the velocity of the electron make with the magnetic field? There are two answers.

What is the direction of the magnetic force on a positive charge that moves as shown in each of the six cases shown in Figure 22.50 below.


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