A current balance used to define the ampere is designed so that the current through it is constant, as is the distance between wires. Even so, if the wires change length with temperature, the force between them will change. What percent change in force per degree will occur if the wires are copper?

Short Answer

Expert verified

The percent change in force per degree is obtained as:\(\left( {17.0{\rm{ }}x{\rm{ }}{{10}^{ - 4}}} \right)\% /^\circ C\).

Step by step solution

01

Define Magnetism

A group of physical characteristics known as magnetism is mediated by magnetic fields. Electric currents and the magnetic moments of elementary particles produce a magnetic field, which then acts on other currents and magnetic moments.

02

Evaluating the percent change in force per degree

We use the equation: \(F = \frac{{{\mu _0}{I_1}{I_2}L}}{{2\pi r}}\)

Noticing that the force is directly proportional to the length of the wire\(\left( L \right)\),keeping the distance\(\left( r \right)\)between two wires and currents\(\left( {{I_{1\;}}and\;{I_2}} \right)\), constant. The equation relating the change in length with the temperature\(\left( T \right)\)is:\(\Delta L = \alpha LT\). From the equation we get-

\(\begin{align}{}\Delta F \propto \Delta L \\\Delta F \propto \alpha T \\\frac{{\Delta F}}{T} \propto \alpha \end{align}\)

So, here the copper wire is: \(\alpha = 17.0 \times {10^{ - 6}}\;^\circ {C^{ - 1}}\).

Therefore, the percent value is obtained as:\(17.0{\rm{ }}x{\rm{ }}{10^{ - 4}}\% /^\circ C\).

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Most popular questions from this chapter

The force on the rectangular loop of wire in the magnetic field in Figure 22.56 can be used to measure field strength. The field is uniform, and the plane of the loop is perpendicular to the field. (a) What is the direction of the magnetic force on the loop? Justify the claim that the forces on the sides of the loop are equal and opposite, independent of how much of the loop is in the field and do not affect the net force on the loop. (b) If a current of 5.00 A is used, what is the force per tesla on the 20.0-cm-wide loop?


Figure 22.56 A rectangular loop of wire carrying a current is perpendicular to a magnetic field. The field is uniform in the region shown and is zero outside that region.

(a) What is the angle between a wire carrying an 8.00Acurrent and the1.20Tfield it is in if 50.0cm of the wire experiences a magnetic force of 2.40N? (b) What is the force on the wire if it is rotated to make an angle of 90º with the field?

A charged particle having mass \({\rm{6}}{\rm{.64 \times 1}}{{\rm{0}}^{{\rm{ - 27}}}}{\rm{\;kg}}\) (that of a helium atom) moving at \({\rm{8}}{\rm{.70 \times 1}}{{\rm{0}}^{\rm{5}}}{\rm{\;m/s}}\) perpendicular to a \({\rm{1}}{\rm{.50 - T}}\) magnetic field travels in a circular path of radius \({\rm{16}}{\rm{.0\;mm}}\).(a)What is the charge of the particle?(b)What is unreasonable about this result?(c)Which assumptions are responsible?

What are the signs of the charges on the particles in Figure 22.46?

What is the direction of the magnetic force on a positive charge that moves as shown in each of the six cases shown in Figure 22.50 below.


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