Are some types of cancer more sensitive to radiation than others? If so, what makes them more sensitive?

Short Answer

Expert verified

The dose of radiation is determined by the location of the tumour in the body and its adhesion to healthy cells.

Step by step solution

01

Definition of cancer

Cancer is a term used to describe a group of diseases characterised by abnormal cell proliferation that has the potential to infiltrate or spread to other regions of the body. Benign tumours, on the other hand, do not spread. A lump, unusual bleeding, a persistent cough, unexplained weight loss, and a change in bowel motions are all possible indications and symptoms. While these signs and symptoms may suggest cancer, they might also signal something else.

02

Explanation for whether some types of cancer are more sensitive to radiation

Cancer cells have a proclivity for rapidly dividing and growing out of control. Radiation treatment destroys dividing cancer cells, but it also kills dividing cells in normal tissues. Damage to normal cells has unfavourable consequences. Radiation treatment is always a delicate balance of eliminating cancer cells while limiting harm to healthy cells.

Therefore, location of the cancer in the body and attachment to healthy cells determines the dose of the radiation.

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Most popular questions from this chapter

(a) Calculate the energy released in the neutron-induced fission (similar to the spontaneous fission in Example\(32.3\)) \(n{ + ^{238}}U{ \to ^{96}}Sr{ + ^{140}}Xe + 3n\), given \(m{(^{96}}Sr) = 95.921750{\rm{ }}u\) and \(m{(^{140}}Xe) = 139.92164{\rm{ }}u\).

(b) This result is about \(6{\rm{ }}MeV\) greater than the result for spontaneous fission. Why?

(c) Confirm that the total number of nucleons and total charge are conserved in this reaction.

Verify by listing the number of nucleons, total charge, and electron family number before and after the cycle that these quantities are conserved in the overall proton-proton cycle in \(2{e^ - } + {4^1}H{ \to ^4}He + 2{\nu _e} + 6\gamma \).

The activities of \(^{131}I\) and \(^{123}I\) used in thyroid scans are given in Table \({\rm{32}}{\rm{.1}}\) to be 50 and \(70\mu Ci\), respectively. Find and compare the masses of \(^{131}I\)and \(^{123}I\) in such scans, given their respective half-lives are \({\rm{8}}{\rm{.04\;d}}\)and \({\rm{13}}{\rm{.2\;h}}\). The masses are so small that the radioiodine is usually mixed with stable iodine as a carrier to ensure normal chemistry and distribution in the body.

Two fusion reactions mentioned in the text are

\(n{ + ^3}He{ \to ^4}He + \gamma \)

and

\(n{ + ^1}H{ \to ^2}H + \gamma \).

Both reactions release energy, but the second also creates more fuel. Confirm that the energies produced in the reactions are \(20.58\) and\(2.22{\rm{ }}MeV\), respectively. Comment on which product nuclide is most tightly bound, \(^4He\) or\(^2H\).

(a) Estimate the years that the deuterium fuel in the oceans could supply the energy needs of the world. Assume world energy consumption to be ten times that of the United States which is \(8 \times {10^9}J/y\) and that the deuterium in the oceans could be converted to energy with an efficiency of \(32\% \). You must estimate or look up the amount of water in the oceans and take the deuterium content to be \(0.015\% \) of natural hydrogen to find the mass of deuterium available. Note that approximate energy yield of deuterium is \(3.37 \times {10^{14}}J/kg\).

(b) Comment on how much time this is by any human measure. (It is not an unreasonable result, only an impressive one.)

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