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Chapter 16: Q9PE (page 590)

Find the frequency of a tuning fork that takes 2.50 x 10-3 s to complete one oscillation.

Short Answer

Expert verified

The time taken by the turning fork is, T = 2.50 x 10-3 s

Step by step solution

01

Identification of the given data

The time taken by the turning fork is, T = 2.50 x 10-3 s

02

Definition of time period

The defined period of time for which a particular event occurs at a specific rate is termed the time period. It can be determined by taking the inverse of the frequency and it is measured in terms of seconds.

03

Determination of frequency

Write the expression for the frequency.

\(f = \frac{1}{T}\)

Here, \(T\) is the time period.

Substitute all the values in the above expression.

\(\begin{aligned}f &= \frac{1}{{2.50 \times {{10}^{ - 3}}\;{\rm{s}}}}\\ &= 400\;{{\rm{s}}^{ - 1}} \times \frac{{1\;{\rm{Hz}}}}{{{{\rm{s}}^{ - 1}}}}\\ &= 400\;{\rm{Hz}}\end{aligned}\)

Thus, the frequency is 400 Hz.

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Most popular questions from this chapter

(a) What is the intensity in W/m2 of a laser beam used to burn away cancerous tissue that, when 90.0% absorbed, puts 500 J of energy into a circular spot 2.00 mm in diameter in 4.00 s?

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