Why does the \({\eta ^0}\) meson have such a short lifetime compared to most other mesons?

Short Answer

Expert verified

As, the \({\eta ^0}\) meson consists of quark-antiquark pairs of the same flavour, its lifetime is short.

Step by step solution

01

Meson

Mesons are hadronic subatomic particles made up of an equal number of quarks and antiquarks, generally one of each, and linked together by strong interactions in particle physics.

02

Lifetime of meson

Unlike the other mesons, that consists of a quark and its appropriate antiquark of the same flavour, such as \({\rm{u\bar u}}\). These quark-antiquark pairs tend to annihilate, which causes its shorter lifetime.

Therefore, due to quark and antiquark, lifetime of meson is short.

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Most popular questions from this chapter

Plans for an accelerator that produces a secondary beam of \({\rm{K}}\)-mesons to scatter from nuclei, for the purpose of studying the strong force, call for them to have a kinetic energy of \({\rm{500 MeV}}\).

(a) What would the relativistic quantity \(\gamma {\rm{ = }}\frac{{\rm{1}}}{{\sqrt {{\rm{1 - }}{{{{\rm{\nu }}^{\rm{2}}}} \mathord{\left/{\vphantom {{{{\rm{\nu }}^{\rm{2}}}} {{{\rm{c}}^{\rm{2}}}}}} \right. \\} {{{\rm{c}}^{\rm{2}}}}}} }}\) be for these particles?

(b) How long would their average lifetime be in the laboratory?

(c) How far could they travel in this time?

The decay mode of the positive tau is\({{\bf{\tau }}^ + } \to {\rm{ }}{{\bf{\mu }}^ + }{\rm{ }} + {\rm{ }}{{\bf{\nu }}_{\bf{\mu }}}{\rm{ }} + {\rm{ }}{{\bf{\bar \nu }}_{\bf{\tau }}}\).

(a) What energy is released?

(b) Verify that charge and lepton family numbers are conserved.

(c) The \({\tau ^ + }\)is the antiparticle of the \({\tau ^ - }\). Verify that all the decay products of the \({\tau ^ + }\)are the antiparticles of those in the decay of the \({\tau ^ - }\) given in the text.

(a) What is the uncertainty in the energy released in the decay of a \(\tau {\rm{ }} - \)due to its short lifetime?

(b) Is the uncertainty in this energy greater than or less than the uncertainty in the mass of the tau neutrino? Discuss the source of the uncertainty.

The primary decay mode for the negative pion \({\pi ^{\rm{ - }}} \to {{\rm{\mu }}^{\rm{ - }}}{\rm{ + }}{{\rm{\bar \upsilon }}_{\rm{\mu }}}\).

(a) What is the energy release in \({\rm{MeV}}\) in this decay?

(b) Using conservation of momentum, how much energy does each of the decay products receive, given the \({\pi ^{\rm{ - }}}\) is at rest when it decays? You may assume the muon antineutrino is massless and has momentum \(p = \frac{{{E_\nu }}}{c}\), just like a photon.

The primary decay mode for the negative pion is \[{\pi ^ - } \to {\mu ^ - } + {\bar \nu _\mu }\]. What is the energy release in MeV in this decay?

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