Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 33: Q8PE (page 1212)

What length track does a \[{{\rm{\pi }}^{\rm{ + }}}\]traveling at 0.100c leave in a bubble chamber if it is created there and lives for \[{\rm{2}}{\rm{.60 \times 1}}{{\rm{0}}^{{\rm{ - 8}}}}{\rm{\;s}}\]? (Those moving faster or living longer may escape the detector before decaying.)

Short Answer

Expert verified

The distance the particle travels is 0.78m.

Step by step solution

01

Definition of distance travelled by particle

The product of half of the sum of beginning velocity, final velocity, and time is the formula for particle distance travelled.

02

Given Data

Speed of particle\(v = 0.100c\)

Lifespan of particle \(t = 2.6 \times {10^{ - 8}}\;{\rm{s}}\;\)

03

Calculating the distance travelled by a particle

The length of the track can be calculated as-

\[\begin{array}{c}D = vt\\ = \left( {0.100 \times 3 \times {{10}^8}\;{\rm{m/s}}} \right) \times \left( {2.60 \times {{10}^{ - 8}}\;\;{\rm{s}}} \right)\\ = 0.78\;\;{\rm{m}}\end{array}\]

Hence, the distance the particle travels is 0.78m.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose a \[{{\rm{W}}^{\rm{ - }}}\]created in a bubble chamber lives for \[{\rm{5}}{\rm{.00 \times 1}}{{\rm{0}}^{{\rm{ - 25}}}}{\rm{\;s}}\]. What distance does it move in this time if it is traveling at \[{\rm{0}}{\rm{.900c}}\]? Since this distance is too short to make a track, the presence of the \[{{\rm{W}}^{\rm{ - }}}\]must be inferred from its decay products. Note that the time is longer than the given \[{{\rm{W}}^{\rm{ - }}}\]lifetime, which can be due to the statistical nature of decay or time dilation.

An antibaryon has three antiquarks with colors\[{\rm{\bar R\bar G\bar B}}\]. What is its color?

Suppose leptons are created in a reaction. Does this imply the weak force is acting? (for example, consider \(\beta \)decay.)

The reaction \({{\rm{\pi }}^{\rm{ + }}}{\rm{ + p}} \to {{\rm{\Delta }}^{{\rm{ + + }}}}\) (described in the preceding problem) takes place via the strong force.

(a) What is the baryon number of the \({{\rm{\Delta }}^{{\rm{ + + }}}}\)particle?

(b) Draw a Feynman diagram of the reaction showing the individual quarks involved.

The primary decay mode for the negative pion \({\pi ^{\rm{ - }}} \to {{\rm{\mu }}^{\rm{ - }}}{\rm{ + }}{{\rm{\bar \upsilon }}_{\rm{\mu }}}\).

(a) What is the energy release in \({\rm{MeV}}\) in this decay?

(b) Using conservation of momentum, how much energy does each of the decay products receive, given the \({\pi ^{\rm{ - }}}\) is at rest when it decays? You may assume the muon antineutrino is massless and has momentum \(p = \frac{{{E_\nu }}}{c}\), just like a photon.
See all solutions

Recommended explanations on Physics Textbooks

Nuclear Physics

Read Explanation

Thermodynamics

Read Explanation

Medical Physics

Read Explanation

Energy Physics

Read Explanation

Physics of Motion

Read Explanation

Atoms and Radioactivity

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free