Theorists have had spectacular success in predicting previously unknown particles. Considering past theoretical triumphs, why should we bother to perform experiments?

Short Answer

Expert verified

Scientists bother to perform experiments to validate the theories and provide live proof for their theories.

Step by step solution

01

Concept Introduction

Particle physics (sometimes known as high-energy physics) is the study of the nature of the particles that make up matter and radiation.

02

Conduction of Experiments

Theorists anticipate the presence of undiscovered particles, but tests are the only way to establish their existence. On the basis of experimental data, a theorist's theory is usually proven to be erroneous.

Einstein dismissed a quantum mechanics-related idea known as spooky activity at a distance. However, by conducting better trials, this notion was subsequently proven to be correct. As a result, conducting tests is required to give proof for any theory.

Therefore, experiments are a proof of a conjecture, so experiments should be carried out.

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Most popular questions from this chapter

(a) Do all particles having strangeness also have at least one strange quark in them?

(b) Do all hadrons with a strange quark also have nonzero strangeness?

The decay mode of the positive tau is\({{\bf{\tau }}^ + } \to {\rm{ }}{{\bf{\mu }}^ + }{\rm{ }} + {\rm{ }}{{\bf{\nu }}_{\bf{\mu }}}{\rm{ }} + {\rm{ }}{{\bf{\bar \nu }}_{\bf{\tau }}}\).

(a) What energy is released?

(b) Verify that charge and lepton family numbers are conserved.

(c) The \({\tau ^ + }\)is the antiparticle of the \({\tau ^ - }\). Verify that all the decay products of the \({\tau ^ + }\)are the antiparticles of those in the decay of the \({\tau ^ - }\) given in the text.

The total energy in the beam of an accelerator is far greater than the energy of the individual beam particles. Why isn't this total energy available to create a single extremely massive particle?

Suppose a \[{{\rm{W}}^{\rm{ - }}}\]created in a bubble chamber lives for \[{\rm{5}}{\rm{.00 \times 1}}{{\rm{0}}^{{\rm{ - 25}}}}{\rm{\;s}}\]. What distance does it move in this time if it is traveling at \[{\rm{0}}{\rm{.900c}}\]? Since this distance is too short to make a track, the presence of the \[{{\rm{W}}^{\rm{ - }}}\]must be inferred from its decay products. Note that the time is longer than the given \[{{\rm{W}}^{\rm{ - }}}\]lifetime, which can be due to the statistical nature of decay or time dilation.

Why is it easier to see the properties of the c, b, and t quarks in mesons having composition W− or t rather than in baryons having a mixture of quarks, such as udb?

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