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Chapter 17: Q15PE (page 629)

What intensity level does the sound in the preceding problem correspond to?

Short Answer

Expert verified

The intensity level is \(84.5\;{\rm{dB}}\).

Step by step solution

01

Given Data

The intensity is \(I = 2.83 \times {10^{ - 4}}\;{\rm{W/}}{{\rm{m}}^{\rm{2}}}\).

02

Sound intensity level

The intensity level is the logarithm of the sound intensity ratio to the threshold intensity—the unit of intensity level in dB.

03

Calculation of the intensity level

Use the intensity level of the sound as,

\({\rm{dB}} = 10\log \frac{I}{{{{10}^{ - 12}}}}\)

Substituting the values we get,

\(\begin{align}{\rm{dB}} &= 10\log \frac{{2.83 \times {{10}^{ - 4}}}}{{{{10}^{ - 12}}}}\\ &= 84.5\;{\rm{dB}}\end{align}\)

Therefore the levels of intensity is \(84.5\;{\rm{dB}}\)

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Most popular questions from this chapter

When you hear a sonic boom, you often cannot see the plane that made it. Why is that?

Question: (a) What is the decibel level of a sound that is twice as intense as a \(90.0\;{\rm{dB}}\)sound? (b) What is the decibel level of a sound that is one-fifth as intense as a \(90.0\;{\rm{dB}}\)?

What are the first three overtones of a bassoon that has a fundamental frequency of 90.0 Hz? It is open at both ends. (The overtones of a real bassoon are more complex than this example, because its double reed makes it act more like a tube closed at one end.)

What is the intensity in watts per meter squared of\(85.0\;{\rm{dB}}\)sound?

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