What is the source of the energy emitted in radioactive decay? Identify an earlier conservation law, and describe how it was modified to take such processes into account.

Short Answer

Expert verified

Source of radiation is Nucleus and Energy is conserved.

Step by step solution

01

Definition of radioactive decay 

According to the quantum theory, it is impossible to anticipate whether a certain atom will experience nuclear disintegration or radioactive decay.

02

Step 2: Source of the energy emitted in radioactive decay    

The spontaneous emission of \({\rm{\alpha }}\)- particles, \({\rm{\beta }}\) particles or \({\rm{\gamma - }}\)radiation from the nuclei of some elements is called radioactivity. The emitted radiations are called nuclear radiation and the element emitting these radiations is called radioactive element.

During radioactivity there is destruction of unstable nuclei and this destruction leads to spontaneous emission of radiation. So source of energy emitted during radioactive decay is nucleus of the atom.

03

Conversion of energy

Earlier law of conservation of energy states that energy neither created nor destroyed but can be transformed into one form of energy to another form of energy. But in radioactivity emission of energy carrying radiation takes place without input of any external energy so here violation of law of energy takes place so for taking the process into account the law modified and states that energy of system remains conserved.

Therefore the source of radiation is Nucleus and Energy is conserved.

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Most popular questions from this chapter

  1. The \(^{{\rm{210}}}\) Po source used in a physics laboratory is labelled as having an activity of \(1.0\,{\rm{\mu Ci}}\) on the date it was prepared. A student measures the radioactivity of this source with a Geiger counter and observes 1500 counts per minute. She notices that the source was prepared 120 days before her lab. What fraction of the decays is she observing with her apparatus?
  2. Identify some of the reasons that only a fraction of the αs emitted are observed by the detector.

Unreasonable Results

The manufacturer of a smoke alarm decides that the smallest current of \({\rm{\alpha }}\) radiation he can detect is \(1.00\,\mu A\).

  1. Find the activity in curies of an \({\rm{\alpha }}\) emitter that produces a \(1.00\,\mu A\)current of \({\rm{\alpha }}\) particles.
  2. What is unreasonable about this result?
  3. What assumption is responsible?

A 5000-Ci \({}^{60}Co\) source used for cancer therapy is considered too weak to be useful when its activity falls to 3500 Ci. How long after its manufacture does this happen?

Cow’s milk produced near nuclear reactors can be tested for as little as \(1.00\,{\rm{pCi}}\) of \({}^{{\rm{131}}}{\rm{I}}\) per litre, to check for possible reactor leakage. What mass of\({}^{{\rm{131}}}{\rm{I}}\) has this activity?

The detail observable using a probe is limited by its wavelength. Calculate the energy of a\({\rm{\gamma }}\)-ray photon that has a wavelength of\(1 \times {10^{ - 16}}\,{\rm{m}}\), small enough to detect details about one-tenth the size of a nucleon. Note that a photon having this energy is difficult to produce and interacts poorly with the nucleus, limiting the practicability of this probe.

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