Question: Dry air is 78.1% nitrogen. What is the partial pressure of nitrogen when the atmospheric pressure is 1.01×105 N/m2?

Short Answer

Expert verified

Answer

The partial pressure of nitrogen is 7.89×104N/m2

Step by step solution

01

Introduction

We apply the formula for partial pressure which is to find partial pressure by multiplying nitrogen percentage by total pressure.

02

Given parameters and formula for partial pressure

Total pressure = Atmospheric pressure =1.01×105N/m2

Percentage of nitrogen =78.1%

The formula for partial pressure Ppartial=% Nitrogen100×Ptotal

Here, Ppartial partial pressure and Ptotal total pressure.

03

Calculate the partial pressure

The partial pressure of nitrogen in the atmosphere

Ppartial=%Nitrogen100×PtotalPpartial=78.1(1.01×105N/m2)100×Ptotal=7.89×104N/m2

Therefore, partial pressure of nitrogen is \({\rm{7}}{\rm{.89 \times 1}}{{\rm{0}}^{\rm{4}}}\;{\rm{N/}}{{\rm{m}}^{\rm{2}}}\)

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