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Chapter 26: Q19PE (page 956)

Repeat the previous problem for glasses that are 1.75 cm from the eyes.

Short Answer

Expert verified

The far point for glasses that are 1.75 cm from the eyes is 26.8 cm.

Step by step solution

01

what is a myopic view?

Myopia is a vision condition in which visual pictures focus in front of the retina of the eye, creating vision problems of distant objects.

02

Given information and Formula to be used

di=1.75cm1m100cm=0.0175m

The power needed (P) to correct the vision can be obtained using the expression,

P=1d0+1di

03

What is her far point for glasses that are 1.75 cm from the eyes?

The power of the lens is equal to the reciprocal of the focal length. therefore,

P=1fP=1d0+1di

Rearrange and solve for the image's distance from the eye, we will get

di=1P-1∞=1-4D-1∞di=-0.25m

Hence, for the glasses that are 1.75 cm from the eyes, the distance between the eye and the image will be - 0.25 m - 0.0175 m = 0.268 m or 26.8 cm

Therefore, the far point for glasses that are 1.75 cm from the eyes is 26.8 cm

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Most popular questions from this chapter

If the lens of a person’s eye is removed because of cataracts (as has been done since ancient times), why would you expect a spectacle lens of about \({\rm{16 D}}\) to be prescribed?

A person with presbyopia has lost some or all of the ability to accommodate the power of the eye. If such a person’s distant vision is corrected with LASIK, will she still need reading glasses? Explain.

(a) During laser vision correction, a brief burst of 193nm ultraviolet light is projected onto the cornea of the patient. It makes a spot 1.00mm in diameter and deposits 0.500mJ of energy. Calculate the depth of the layer ablated, assuming the corneal tissue has the same properties as water and is initially at 34.00C. The tissue’s temperature is increased to 1000Cand evaporated without further temperature increase. (b) Does your answer imply that the shape of the cornea can be finely controlled?

(a) Where does an object need to be placed relative to a microscope for its 0.500 cmfocal length objective to produce a magnification of -400? (b) Where should the 5.00 cm focal length eyepiece be placed to produce a further fourfold ( 4.00 ) magnification?

When laser light is shone into a relaxed normal-vision eye to repair a tear by spot-welding the retina to the back of the eye, the rays entering the eye must be parallel. Why?
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