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Chapter 26: Q2PE (page 956)
Unless otherwise stated, the lens-to-retina distance is 2.00 cm.
Calculate the power of the eye when viewing an object 3.00 maway.
The power of the eye when viewing an object 3.00 m away is, P = +50.34 D.
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(a) Where does an object need to be placed relative to a microscope for its 0.500 cmfocal length objective to produce a magnification of -400? (b) Where should the 5.00 cm focal length eyepiece be placed to produce a further fourfold ( 4.00 ) magnification?
A boy has a near point of 50 cm and a far point of 500 cm. Will a –4.00 D lens correct his far point to infinity?
The contact lens prescription for a nearsighted person is -4.00 D and the person has a far point of 22.5 cm. What is the power of the tear layer between the cornea and the lens if the correction is ideal, taking the tear layer into account?
An amoeba is 0.305 cm away from the 0.300 cm focal length objective lens of a microscope. (a) Where is the image formed by the objective lens? (b) What is this image’s magnification? (c) An eyepiece with a 2.00 cm focal length is placed 20.0 cm from the objective. Where is the final image? (d) What magnification is produced by the eyepiece? (e) What is the overall magnification? (See Figure 26.16.)
A student’s eyes, while reading the blackboard, have a power of 51.0 D. How far is the board from his eyes?
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