Find the largest wavelength of light falling on double slits separated by 1.20 µm for which there is a first-order maximum. Is this in the visible part of the spectrum?

Short Answer

Expert verified

The largest wavelength of light falls on double slits separated1200nm and this is beyond the visible spectrum.

Step by step solution

01

Given data

The separation between the two slits isd=1.20μm10-6m1μm=1.20×10-6m

02

Finding the wavelength of the light

A formula for the angle of the first-order maximum can be expressed as,

dsinθ=λ..................................(1)

Substituting the given data in equation (1), we get,

(1.20'10-6m)'sinθ=λ..........................(2)

For the highest wavelength, we can consider that the

For the largest wavelength, λmaxthe value ofsinθ=1, therefore, we get from the equation (2), that

λmax=1.2×10-5m×1=1.2×10-6m1nm10-9m=1200nm

Thus, the largest wavelength of light is 1200nm.

This wavelength will not appear in the visible spectrum which exists between 380nm to 760 nm.

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