Chapter 27: Q19PE (page 997)

Using the result of the problem above, calculate the distance between fringes for $^{633 nm}$ light falling on double slits separated by $^{0.0800 mm}$ , located $^{3.00 m}$ from a screen as in Figure $^{27.56}$ .

Short Answer

Expert verified

The distance between the fringes is $^{2.37 cm}$ .

Step by step solution

Given data

The wavelength used for the interference is $λ = 633 nm (\frac{10^{- 9} m}{1 nm}) = 6.33 \times 10^{- 7} m$

The separation between the slits is $d = 0.0800 mm (\frac{10^{- 3} m}{1 mm}) = 8.00 \times 10^{- 5} m$

The distance of the screen is x=3.00 m.

Evaluating the distance

Using the result of the question solved before, we then observe that: $∆ y = \frac{x λ}{d}$ .

We then substitute this equation using the given values in the problem.

Then, we get:

$∆ y = \frac{x λ}{d} = \frac{3.00 m \times (6.33 \times 10^{- 7} m)}{8.00 \times 10^{- 5} m} = 0.0237 m (\frac{100 cm}{1 m}) = 2.37 cm$

Therefore, the distance between the fringes is $^{2.37 cm}$ .

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Using the result of the problem above, calculate the distance between fringes for $^{633 nm}$ light falling on double slits separated by $^{0.0800 mm}$ , located $^{3.00 m}$ from a screen as in Figure $^{27.56}$ .

Short Answer

Step by step solution

Given data

Evaluating the distance

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Using the result of the problem above, calculate the distance between fringes for 633nm light falling on double slits separated by 0.0800mm, located 3.00mfrom a screen as in Figure 27.56.

Short Answer

Step by step solution

Given data

Evaluating the distance

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Fluids

Electricity and Magnetism

Astrophysics

Engineering Physics

Nuclear Physics

Medical Physics

Study anywhere. Anytime. Across all devices.

Using the result of the problem above, calculate the distance between fringes for $^{633 nm}$ light falling on double slits separated by $^{0.0800 mm}$ , located $^{3.00 m}$ from a screen as in Figure $^{27.56}$ .