Chapter 27: Q8PE (page 997)

What is the separation between two slits for which 610-nm orange light has its first maximum at an angle of $^{30.0 °}$ ?

Short Answer

Expert verified

The separation between two slits is $^{1.22' 10^{- 8} m}$ .

Step by step solution

Given data

The wavelength of the orange light is $^{λ = 610 nm (\frac{10^{- °} m}{1 nm}) = 6.1 \times 10^{- 7} m}$

The angle for the first maximum is $^{30.0 °}$

Finding the separation between two slits

A formula for the angle of the first-order maximum can be expressed as,

$dsin θ = λ$ ………………………….(1)

Substituting the given data in equation (1), we get,

$d \times \sin (30.0 °) = 6.1 \times 10^{7} m d = (\frac{6.1 \times 10^{7} m}{0.5}) d = 1.22 \times 10^{- 6} m$

Thus, the separation between two slits is $^{1.22' 10^{- 6} m}$ .

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What is the separation between two slits for which 610-nm orange light has its first maximum at an angle of $^{30.0 °}$ ?

Short Answer

Step by step solution

Given data

Finding the separation between two slits

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What is the separation between two slits for which 610-nm orange light has its first maximum at an angle of30.0°?

Short Answer

Step by step solution

Given data

Finding the separation between two slits

One App. One Place for Learning.

Most popular questions from this chapter

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Medical Physics

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Study anywhere. Anytime. Across all devices.

What is the separation between two slits for which 610-nm orange light has its first maximum at an angle of $^{30.0 °}$ ?