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Chapter 27: Q9PE (page 997)

Find the distance between two slits that produces the first minimum for 410-nm violet light at an angle of 45.0º.

Short Answer

Expert verified

The distance between two slits that produces the first minimum is 2.9'10-7.

Step by step solution

01

Given data

The wavelength of the violet light is λ=410nm10-9m1nm=4.1×10-7m

The angle for the first maximum is 45.0°

02

Finding the separation between two slits

A formula for the angle of the first-order minimum can be expressed as,

dsinθ=12λ………………………….(1)

Substituting the given data in equation (1), we get,

d×sin45.0°=12×4.1×10-7md×sin45°=2.05×10-7md=2.05×10-7m0.707d=2.9×10-7m

Thus, the distance between two slits is 2.9'10-7m.

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Most popular questions from this chapter

(a) Show that a 30,000-line-per-centimeter grating will not produce a maximum for visible light. (b) What is the longest wavelength for which it does produce a first-order maximum? (c) What is the greatest number of lines per centimeter a diffraction grating can have and produce a complete second-order spectrum for visible light?

Red light of wavelength of 700 nm falls on a double slit separated by 400 nm. (a) At what angle is the first-order maximum in the diffraction pattern? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?

Explain what happens to the energy carried by light that it is dimmed by passing it through two crossed polarizing filters.

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