Recursion A useful feature of user-defined functions is recursion, the ability of a function to call itself. For example, consider the following definition' of the factorial \(n !\) of a positive integer \(n\) : $$ n != \begin{cases}1 & \text { if } n=1 \\ n \times(n-1) ! & \text { if } n>1\end{cases} $$ This constitutes a complete definition of the factorial which allows us to calculate the value of \(n !\) for any positive integer. We can employ this definition directly to create a Python function for factorials, like this: def factorial \((\mathrm{n}):\) if \(\mathrm{n}==1:\) return 1 else: return \(\mathrm{n} *\) factorial \((\mathrm{n}-1)\) Note how, if \(n\) is not equal to 1 , the function calls itself to calculate the factorial of \(n-1\). This is recursion. If we now say "print (factorial (5))" the computer will correctly print the answer 120 .

Short Answer

Expert verified
The factorial of 5 is calculated as \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\) using the recursive function.

Step by step solution

01

Understand the Problem Definition

The problem is to calculate the factorial of a positive integer using recursion. The definition of factorial is given as: 1. If \(n = 1\), then \(n! = 1\) 2. If \(n > 1\), then \(n! = n \times (n - 1)!\)
02

Recursion Explanation

Recursion is a process where a function calls itself. Here, the factorial function calls itself with the argument \(n-1\) until the base case, \(n=1\), is reached.
03

Python Function Definition

The given Python function is defined as follows: ```python def factorial(n): if n == 1: return 1 else: return n * factorial(n-1) ``` This function works by checking if \(n\) is 1. If true, it returns 1. Otherwise, it recursively calls itself with \(n-1\) and multiplies the result by \(n\).
04

Execute the Function

To calculate the factorial of 5, we call the function as follows: ```python print(factorial(5)) ``` This will compute \(5! = 5 \times 4 \times 3 \times 2 \times 1 = 120\).
05

Detailed Execution of factorial(5)

Here is the step-by-step breakdown of calculating \(5!\): 1. factorial(5) = 5 * factorial(4) 2. factorial(4) = 4 * factorial(3) 3. factorial(3) = 3 * factorial(2) 4. factorial(2) = 2 * factorial(1) 5. factorial(1) = 1 Combining these steps, we get \(5! = 5 * 4 * 3 * 2 * 1 = 120\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

factorial function
The factorial function is a mathematical function that multiplies a number by every integer less than it down to 1. It's represented by an exclamation mark (!) after the number. For example, the factorial of 5 (written as 5!) is equal to 5 × 4 × 3 × 2 × 1. This gives us the value 120.
Factorials are commonly used in permutations, combinations, and other areas of mathematics.
The general rule for factorials is:
  • If \(n = 1\), then \(n! = 1\)
  • If \(n > 1\), then \(n! = n \times (n - 1)!\)

This second rule shows the recursive nature of the factorial function, as it refers to the function itself for its calculation.
Python functions
Python functions are blocks of reusable code designed to perform specific tasks. They help in organizing code and making it more modular.
A Python function is defined using the 'def' keyword, followed by the function name and parentheses (). Here is the syntax to define a function:
```python
def function_name(parameters):
# code block
return result
```
In our factorial example, the function is defined as follows:
```python
def factorial(n):
if n == 1:
return 1
else:
return n * factorial(n-1)
```
This function checks if the number is 1. If true, it returns 1. Otherwise, it calls itself with \(n-1\) and multiplies the result by \(n\).
Notice the use of 'if' and 'else' to handle different cases.
recursive algorithms
A recursive algorithm is an algorithm that solves a problem by solving smaller instances of the same problem. This process continues until it hits a base case, which is solved directly without further recursion.
Key components of a recursive algorithm are:
  • Base case: The condition under which recursion ends.
  • Recursive step: The process of reducing the problem into smaller instances and calling the function itself.

In the factorial function example, the base case is when \(n = 1\), returning 1. The recursive step is when the function calls itself with \(n - 1\).
Recursive algorithms are powerful but can lead to stack overflow if not handled correctly, as each function call adds a new layer to the call stack. Always ensure that recursive algorithms have well-defined base cases to avoid infinite recursion.

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Most popular questions from this chapter

Another ball dropped from a tower A ball is again dropped from a tower of height \(h\) with initial velocity zero. Write a program that asks the user to enter the height in meters of the tower and then calculates and prints the time the ball takes until it hits the ground, ignoring air resistance. Use your program to calculate the time for a ball dropped from a \(100 \mathrm{~m}\) high tower.

The semi-empirical mass formula In nuclear physics, the semi-empirical mass formula is a formula for calculating the approximate nuclear binding energy \(B\) of an atomic nucleus with atomic number \(Z\) and mass number \(A\) : $$ B=a_{1} A-a_{2} A^{2 / 3}-a_{3} \frac{Z^{2}}{A^{1 / 3}}-a_{4} \frac{(A-2 Z)^{2}}{A}+\frac{a_{5}}{A^{1 / 2}} $$ where, in units of millions of electron volts, the constants are \(a_{1}=15.8, a_{2}=18.3\), \(a_{3}=0.714, a_{4}=23.2\), and $$ a_{5}= \begin{cases}0 & \text { if } A \text { is odd, } \\ 12.0 & \text { if } A \text { and } Z \text { are both even, } \\ -12.0 & \text { if } A \text { is even and } Z \text { is odd. }\end{cases} $$ a) Write a program that takes as its input the values of \(A\) and \(Z\), and prints out the binding energy for the corresponding atom. Use your program to find the binding energy of an atom with \(A=58\) and \(Z=28\). (Hint: The correct answer is around \(500 \mathrm{MeV}\) ) b) Modify your program to print out not the total binding energy B, but the binding energy per nucleon, which is \(B / A\). c) Now modify your program so that it takes as input just a single value of the atomic number \(Z\) and then goes through all values of \(A\) from \(A=Z\) to \(A=3 Z\), to find the one that has the largest binding energy per nucleon. This is the most stable nucleus with the given atomic number. Have your program print out the value of \(A\) for this most stable nucleus and the value of the binding energy per nucleon d) Modify your program again so that, instead of taking \(Z\) as input, it runs through all values of \(Z\) from 1 to 100 and prints out the most stable value of \(A\) for each one. At what value of \(Z\) does the maximum binding energy per nucleon occur? (The true answer, in real life, is \(Z=28\), which is nickel.)

Altitude of a satellite A satellite is to be launched into a circular orbit around the Earth so that it orbits the planet once every \(T\) seconds. a) Show that the altitude \(h\) above the Earth's surface that the satellite must have is $$ h=\left(\frac{G M T^{2}}{4 \pi^{2}}\right)^{1 / 3}-R $$ where \(G=6.67 \times 10^{-11} \mathrm{~m}^{3} \mathrm{~kg}^{-1} \mathrm{~s}^{-2}\) is Newton's gravitational constant, \(M=\) \(5.97 \times 10^{24} \mathrm{~kg}\) is the mass of the Earth, and \(R=6371 \mathrm{~km}\) is its radius. b) Write a program that asks the user to enter the desired value of \(T\) and then calculates and prints out the correct altitude in meters. c) Use your program to calculate the altitudes of satellites that orbit the Earth once a day (so-called "geosynchronous" orbit), once every 90 minutes, and once every 45 minutes. What do you conclude from the last of these calculations? d) Technically a geosynchronous satellite is one that orbits the Earth once per sidereal day, which is \(23.93\) hours, not 24 hours. Why is this? And how much difference will it make to the altitude of the satellite?

Suppose arrays a and b are defined as follows: $$ \begin{aligned} &\text { from numpy import array } \\ &a=\operatorname{array}([1,2,3,4], \text { int }) \\ &b=\operatorname{array}([2,4,6,8], \text { int }) \end{aligned} $$ What will the computer print upon executing the following lines? (Try to work out the answer before trying it on the computer.) a) print \((b / a+1)\) b) print \((b /(a+1))\) c) print(1/a)

Quantum potential step A well-known quantum mechanics problem involves a particle of mass \(m\) that encounters a one-dimensional potential step, like this: The particle with initial kinetic energy \(E\) and wavevector \(k_{1}=\sqrt{2 m E} / \hbar\) enters from the left and encounters a sudden jump in potential energy of height \(V\) at position \(x=0\). By solving the Schrödinger equation, one can show that when \(E>V\) the particle may either (a) pass the step, in which case it has a lower kinetic energy of \(E-V\) on the other side and a correspondingly smaller wavevector of \(k_{2}=\sqrt{2 m(E-V)} / \hbar\), or \((b)\) it may be reflected, keeping all of its kinetic energy and an unchanged wavevector but moving in the opposite direction. The probabilities \(T\) and \(R\) for transmission and reflection are given by $$ T=\frac{4 k_{1} k_{2}}{\left(k_{1}+k_{2}\right)^{2}}, \quad R=\left(\frac{k_{1}-k_{2}}{k_{1}+k_{2}}\right)^{2} . $$ Suppose we have a particle with mass equal to the electron mass \(m=9.11 \times\) \(10^{-31} \mathrm{~kg}\) and energy \(10 \mathrm{eV}\) encountering a potential step of height \(9 \mathrm{eV}\). Write a Python program to compute and print out the transmission and reflection probabilities using the formulas above.

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