The following problems have little value but might prove interesting as intellectual exercises. (a) Is it possible to construct a network of resistors which cannot be reduced by using the series and parallel formulae together with the delta-Y or Y - delta transformation? (b) An infinite triangular mesh of \(1 \Omega\) resistors is constructed in a plane. What is the equivalent resistance between two adjacent nodes? (c) Nine resistors are of identical appearance but eight are of \(1 \Omega\) while the ninth is of \(2 \Omega\). Can a two-terminal network be constructed out of these resistors of such a form that one measurement of resistance across it would enable the odd resistor to be unambiguously selected?

Short Answer

Expert verified
Answer: No, it is not possible to construct a non-reducible network of resistors as they can always be simplified using either a series, parallel, or Δ-Y or Y-Δ transformation.

Step by step solution

01

Understanding Reducible and Non-Reducible Network of Resistors

To answer this question, first, we need to understand what constitutes a reducible network of resistors. A reducible network of resistors is one that can be simplified into a single equivalent resistor using series, parallel, or Δ-Y or Y-Δ transformations. In contrast, a non-reducible network of resistors is a network that cannot be simplified into a single equivalent resistor using any of those transformations.
02

Non-Reducible Network Conclusion

After understanding the definitions of reducible and non-reducible networks, we can deduce that it is impossible to construct a non-reducible network using resistors as they can always be simplified using either a series, parallel, or Δ-Y or Y-Δ transformation. #Problem (b): Equivalent Resistance in Infinite Triangular Mesh#
03

Identify the Repeating Unit

We can solve this problem by identifying the repeating unit within the triangular mesh and applying the Y-Δ transformation to that unit.
04

Apply Y-Δ Transformation

Applying the Y-Δ transformation to the repeating unit of the triangular mesh simplifies the problem. After simplification, we get an equivalent circuit with one resistor connected to the other through a third resistor.
05

Calculate Equivalent Resistance

Let the equivalent resistance between two adjacent nodes be R. For this simplified circuit, we can write an equation relating R to the resistances of the resistors in the circuit: \(R = \frac{1}{3} (1 + R)\)
06

Solve for R

Solving this equation for R gives us the equivalent resistance between two adjacent nodes: \(R = \frac{1}{2} \Omega\) #Problem (c): Identifying the Odd Resistor#
07

Construct Wheatstone Bridge

To determine if we can identify the 2Ω resistor, we can construct a Wheatstone bridge using the nine resistors given. In a balanced Wheatstone bridge, the ratio of resistances in one branch is equal to the ratio of resistances in the other branch.
08

Create Two Branches

We create two branches of the Wheatstone bridge: 1. Branch 1: Contains four 1Ω resistors connected in series (total of 4Ω). 2. Branch 2: Contains two 1Ω resistors, the 2Ω resistor, and another 1Ω resistor connected in series (total of 5Ω).
09

Measure Resistance Across Bridge

When a Wheatstone bridge is balanced, the resistance across it will be equal to the ratio of the total resistance of the branches. In this case, we have: \(\frac{R_{total}}{R} = \frac{5}{4}\)
10

Identify Odd Resistor

The measured resistance R across the Wheatstone bridge is not equal to any of the resistances in the given network (1Ω or 2Ω). Therefore, the odd resistor (2Ω) can be unambiguously identified by constructing this two-terminal network and performing one measurement of resistance across it.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Resistor Network Analysis
Resistor network analysis is the method of finding the equivalent resistance of a complex circuit. The network consists of various resistors connected together in series, parallel, or a combination thereof. By understanding the properties of these connections, you can replace the entire network with a single resistor that has the same resistance as the original network. This simplification process relies heavily on series and parallel formulae, delta-Y and Y-delta transformations. For instance, in the context of the provided exercise, a non-reducible network is theoretically impossible as it can always be simplified to an equivalent resistance.

Analyzing resistor networks is fundamental in electrical engineering as it helps in designing circuits with the desired properties and in power management within the circuitry. At a basic level, the goal is to use the formulas for resistors in series and in parallel to simplify the network as much as possible, and for more complex interconnected networks, to use delta-Y and Y-delta transformations.
Series and Parallel Circuits
When resistors are connected end-to-end, it's known as a series circuit where the current flowing through each resistor is the same. The total resistance of a series circuit is the sum of the individual resistances. In contrast, a parallel circuit happens when resistors are connected across the same two points, thus all the resistors have the same voltage across them. The total resistance of resistors in parallel is found by using the formula: \(\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \ldots + \frac{1}{R_n}\). In practical scenarios, like the one in the textbook exercise, these principles are foundational to determining the equivalent resistance across a network, as every complex network can be broken down into series and parallel components.
Delta-Y and Y-Delta Transformations
Delta-Y (Δ-Y) and Y-Delta (Y-Δ) transformations are techniques used to simplify resistor networks that can't be reduced using just the simple series and parallel arrangements. These transformations allow us to convert a triangle (delta or Δ) configuration of resistors into a Y (star) shape, and vice versa. This is particularly useful for networks where series and parallel rules alone do not apply, such as the infinite triangular mesh in the textbook problem. In this case, a Δ-Y transformation simplifies the recurring pattern within the mesh, ultimately enabling the calculation of equivalent resistance, which would otherwise be a challenging task.
Wheatstone Bridge
The Wheatstone bridge is a circuit used to measure an unknown electrical resistance by balancing two legs of a bridge circuit. One leg contains the unknown component, while the other leg has resistors with known resistances. When the bridge is balanced, the ratio of the known resistors in one leg is equal to the ratio in the other leg, thus allowing determination of the unknown resistance. This concept was applied in the exercise to identify the resistor with a different value. By creating a network and measuring the resistance across, the odd resistor can be unambiguously selected due to the characteristics of the balanced Wheatstone bridge.
Infinite Network Analysis
Infinite network analysis involves assessing a resistor network that extends infinitely. The challenge here is that traditional methods for calculating equivalent resistance don't work because there are an infinite number of resistors. However, thanks to principles of symmetry and by observing repeating patterns, you can often find a finite equivalent resistance. This was demonstrated in the textbook exercise, where an infinite triangular mesh was effectively reduced by applying a Y-Δ transformation and identifying a repeating pattern, thus arriving at a solvable equation for equivalent resistance.
Equivalent Resistance Calculation
The equivalent resistance calculation is the process of determining a simplified resistance for a complex circuit. It is the total resistance that a current would face if the entire network were replaced with a single resistor. This calculation can be straightforward for simple series or parallel circuits but may require iterative techniques and transformations for more complex configurations. As we saw in the problems posed, understanding how to approach the network - whether by series/parallel analysis or by more advanced transformations - is key to finding that single, equivalent resistance value.

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Most popular questions from this chapter

A d.c. source has an electromotance of \(120 \mathrm{~V}\) and a negligible internal resistance. If \(n\) cells, each of electromotance \(2.1 \mathrm{~V}\) and internal resistance \(0.1 \Omega\), are to be charged from this source with a charging current of \(3 \mathrm{~A}\), find the series resistance necessary. If \(n=20\), what proportion of energy delivered by the source is wasted as heat? Find also the potential difference across the 20 cells.

A capacitor of capacitance \(C_{1}\) has a charge \(Q_{0}\) on its plates. It is connected at time \(t=0\) in series with a capacitor of capacitance \(C_{2}\) and a resistor \(R\) by the closing of a switeh. Find the time constant of the ensuing discharge.

A d.c generator in series with a resistance \(R\) is connected in parallel with both a battery of electromotance \(12 \mathrm{~V}\) and a resistive load. The electromotance of the generator may fluctuate, and \(R\) is of such a value that all the current to the load is supplied by the generator when its electromotance is \(60 \mathrm{~V}\). What fraction of the current does it supply when its electromotance drops to \(50 \mathrm{~V}\) ? Neglect the internal resistances of the generator and battery.

Three of the four arms of a Wheatstone bridge network are of \(40 \Omega\), the fourth is \(41 \Omega\) and the resistance of the detector is \(20 \Omega\). If the driving source has an electromotance of \(2 \mathrm{~V}\) and negligible internal resistance, find the current through the detector using Kirchhoff's laws.

A steady current flows across the plane boundary between two conductors of conductivities \(\sigma_{1}\) and \(\sigma_{2}\). Find a relation between the angles \(\theta_{1}\) and \(\theta_{2}\) which the current flow makes with the normal to the boundary on the two sides. What will be the effect if one conductor is a metal and the other an electrolyte?

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