Chapter 7: Problem 13
Photoclectrons are liberated from a plate by ultraviolet radiation, their initial velocity being negligible. A magnetic field \(\mathbf{B}\) is maintained parallel to the plate and an E-field perpendicular to it. The E-field is produced by a second plate parallel to the first, a distance \(d\) from it and at a positive potential \(V\) with respect to it. Show that the value of \(d\) for which the current just fails to pass between the plates is \(\left(2 m, V / e B^{2}\right)^{1 / 2}\), where e and \(m_{e}\) are the charge and mass of the clectron.
Short Answer
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