A sphere of radius \(a\) is magnetized uniformly parallel to a diameter so, that its magnetic moment per unit volume is \(M\). Find the B-field at a distance \(r\) from the centre for \(r>a\) and \(r

Short Answer

Expert verified
Answer: The expressions for the magnetic field B are as follows: 1. For outside the sphere (r > a): B(r > a) = (μ0 * M * a^3) / (3 * r^3) 2. For inside the sphere (r < a): B(r < a) = (μ0 * M * r) / 3

Step by step solution

01

Understand the concept of the magnetic moment

Magnetic moment is a measure of the magnetic strength of a magnetized object. In this case, the magnetic moment per unit volume is given as M. The total magnetic moment of the sphere can be found by multiplying M by the volume of the sphere.
02

Calculate the total magnetic moment

The total magnetic moment of the sphere is given by M times its volume. The sphere's volume can be calculated as (4/3)πa^3, where a is the radius of the sphere. Therefore, the total magnetic moment μ is given by: μ = M * (4/3)πa^3
03

Divide the sphere into two spheres of poles

As suggested, we can treat the sphere of dipoles as two spheres of poles (positive and negative) slightly displaced from each other along the diameter. This simplification allows us to use expressions derived for a charged sphere when finding the B-field for the magnetized sphere.
04

Calculate the B-field (r > a)

For a point outside the sphere (r > a), the magnetic field is the same as that of a point dipole at the center of the sphere: B = (μ0 * μ) / (4 * π * r^3) Substitute the total magnetic moment μ from step 2: B = (μ0 * M * (4/3)πa^3) / (4 * π * r^3)
05

Simplify the B-field expression (r > a)

The magnetic field B(r > a) now simplifies to: B(r > a) = (μ0 * M * a^3) / (3 * r^3)
06

Calculate the B-field (r < a)

For a point inside the sphere (r < a), the magnetic field is the same as that produced by an effective point dipole proportional to the volume of the sphere enclosed by r: B = (μ0 * (M * (4/3)πr^3)) / (4 * π * r^3)
07

Simplify the B-field expression (r < a)

The magnetic field B(r < a) now simplifies to: B(r < a) = (μ0 * M * r) / 3
08

Final results

For the given uniformly magnetized sphere, the magnetic field B at a distance r from the center can be described as follows: 1. For r > a (outside the sphere): B(r > a) = (μ0 * M * a^3) / (3 * r^3) 2. For r < a (inside the sphere): B(r < a) = (μ0 * M * r) / 3

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Moment
The magnetic moment is a fundamental concept in understanding magnetism and is often introduced when learning about how objects can influence magnetic fields. It is a vector quantity, represented by the symbol \( \mu \), that measures the strength and direction of a magnetic source.

In the context of magnetostatics, which is the study of magnetic fields in systems with steady currents or permanent magnets, the magnetic moment characterizes the entire magnetic behavior of a magnetized object. For example, when a sphere is uniformly magnetized, each unit volume contributes a small magnetic moment to the whole. These moments are directed along the magnetization direction and sum up to give the sphere's total magnetic moment.

To calculate the total magnetic moment, as mentioned in the step-by-step solution, one multiplies the magnetic moment per unit volume, \( M \), by the volume of the sphere. Mathematically, this is \( \mu = M \times \frac{4}{3}\pi a^3 \), where \( a \) is the radius of the sphere. Understanding this concept is crucial when dealing with the resulting magnetic field both inside and outside the magnetized object.

One interesting trait about magnetic moments is that they are the source of magnetic fields in the absence of electric currents. In our everyday life, this property is utilized in various devices such as compass needles, which align with the Earth's magnetic field due to their own magnetic moments.
Magnetostatics
Magnetostatics is a branch of physics focused on the behavior of magnetic fields in systems where the currents are steady, meaning they don't change with time. This field of study rests on the assumption that steady currents produce static magnetic fields, which is a reasonable approximation in many real-world scenarios.

The governing laws of magnetostatics include Ampere's Law and the magnetic field analogue of Gauss's Law for electricity, which states that the net magnetic flux through a closed surface is always zero. This is because magnetic fields do not originate or terminate at any point; instead, they form closed loops. A magnetized sphere, as in the textbook example, falls under the category of problems solvable with these laws since the magnetization produces a static and predictable framework for magnetic fields.

In the provided solution, magnetostatics is applied by using the dipole approximation to calculate the magnetic field inside and outside the sphere. This approach simplifies the problem, allowing for the use of expressions derived for static electric charges, which are closely related to their magnetic counterparts in terms of mathematical form.

Relevance in Everyday Life

Understanding magnetostatics isn't just for academic exploration; it's integral in designing electromagnetic devices, like electric motors and generators, which operate on the principles of steady magnetic fields.
Dipole Approximation
In the study of magnetic fields, the dipole approximation is a simplifying assumption that allows for an easier computation of fields around magnetic sources. The approximation considers the magnetic source as a magnetic dipole with a north and a south pole, analogous to the positive and negative charges in electric fields.

This approximation is valid when the distance from the magnetic source is relatively large compared to the size of the source itself. Consequently, the complex distribution of the magnetic material is reduced to a simple model, characterized solely by its magnetic moment.

When applying the dipole approximation to our problem of a magnetized sphere, the sphere behaves like a bar magnet with a north and south pole at opposite ends of a diameter. This treatment is exceptionally useful because it reduces a potentially complicated three-dimensional magnetized volume to a point dipole located at the center for calculations outside the sphere (\(r > a\)).

Inside the sphere (\(r < a\)), the dipole approximation still holds, but with a different interpretation. The magnetic field at any point inside is due to the magnetization of the volume of the sphere enclosed by the radius \(r\). No need to consider the rest of the sphere material outside this radius because, as per the magnetic Gauss’s Law, the contribution cancels out.

By mastering the dipole approximation, students can tackle a wide variety of magnetic field problems with greater ease, a testament to the power of mathematical simplifications in physics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Two flat coils each of 10 turns have mean radii of \(20 \mathrm{~cm}\) and are placed coaxially \(1 \mathrm{~cm}\) apart. Find the approximate force between them if they both carry \(5 \mathrm{~A}\) in the same sense.

Modern magnetometers for measuring B-fields are described in Comment C12.2. In the older vibration magnetometer, a small permanent dipole was allowed to perform small angular oscillations in a horizontal plane first in a standard field \(\mathbf{B}_{0}\) and then in the unknown \(\mathrm{B}\). If the periods of oscillation were, respectively, \(T_{0}\) and \(T\), show that \(B=B_{0} T_{6}^{2} T^{2}\),

Take a small rectangular current loop of sides \(\mathrm{d} x\), dy situated at the origin in the xy plane and carrying a current \(I\) round its four sides. Find the B-field at a. field point P a great distance from the loop along the \(x\) axis. Show that the field has the form \(\mu_{0} m /\left(4 \pi x^{3}\right)\), where \(m\) is its dipole moment. (Note that all four sides produce a field.)

A light circular flexible loop of radius a carries a current \(I\) and is placed in a plane perpendicular to a uniform B-field. Find the tension in the loop.

Photoclectrons are liberated from a plate by ultraviolet radiation, their initial velocity being negligible. A magnetic field \(\mathbf{B}\) is maintained parallel to the plate and an E-field perpendicular to it. The E-field is produced by a second plate parallel to the first, a distance \(d\) from it and at a positive potential \(V\) with respect to it. Show that the value of \(d\) for which the current just fails to pass between the plates is \(\left(2 m, V / e B^{2}\right)^{1 / 2}\), where e and \(m_{e}\) are the charge and mass of the clectron.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free